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Philosophaie
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What happens if you have to take the arccos of a number greater than 1 or less than -1.
I know from a right triangle if you have:
[ tex ]\Theta[ /tex ]=arccos(x)
if you use x as the adjacent side, 1 as the hypotenuse and [ tex ]\sqrt{1-x^2}[ /tex ] as the opposite.
Is that where the negative sign start?
I have an equation that has numbers from -1.01 to 1.01 as inputs "x". The output runs from 0 to 180 without the numbers 180 to 359 or any negative numbers.
Where do I find the negative or the higher angles?
I know from a right triangle if you have:
[ tex ]\Theta[ /tex ]=arccos(x)
if you use x as the adjacent side, 1 as the hypotenuse and [ tex ]\sqrt{1-x^2}[ /tex ] as the opposite.
Is that where the negative sign start?
I have an equation that has numbers from -1.01 to 1.01 as inputs "x". The output runs from 0 to 180 without the numbers 180 to 359 or any negative numbers.
Where do I find the negative or the higher angles?
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