Understanding Basis for Solving Linear Algebra Problems

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In summary, the conversation is about finding bases for vector spaces and solving related questions. The concept of a basis is described as a set of vectors or matrices that are linearly independent and span the space. The examples given involve finding a basis for a set of polynomials and a set of 2x2 matrices.
  • #1
ElliottG
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Hey guys

There are so many of these damn "Find a basis" questions and I can't get any of them because we never directly learned how...or she never showed us in class...my final exam is tomorrow.

Here are some examples of questions:

http://184.154.165.18/~devilthe/uploads/1323453294.png

http://184.154.165.18/~devilthe/uploads/1323430492.png

Part D

I have zero idea how they solve these...

I know that a basis is a linearly independent spanning set...but how to solve these questions? No idea.

Can there be more than one basis for a question?

Thanks,
Elliott
 
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  • #2
A basis is a set of vectors (or matrices in this problem) that is linearly independent and spans the (sub)space. A vector (sub)space can have many bases.

For d, start by playing with the equation that defines the subspace V, using an arbitrary matrix X, where
[tex]X = \begin{bmatrix}a & b \\ c & d \end{bmatrix}[/tex]
 
  • #3
Any polynomial, of degree 2, is of the form [itex]p(x)= ax^2+ bx+ c[/itex]. [itex]p'(x)= 2ax+ b[/itex] Requiring that p'(1)= 0 means that 2a+ b= 0 so b= -2a. That is, for any p in this set, [itex]p(x)= ax^2- 2ax+ c= a(x^2- 2)+ c(1)[/itex]. Now, what is a basis for that set?

Any 2 by 2 matrix is of the form
[tex]\begin{bmatrix}a & b \\ c & d\end{bmatrix}[/tex]

We require that
[tex]\begin{bmatrix}1 & 0 \\ 0 & -1\end{bmatrix}\begin{bmatrix}a & b \\ c & d\end{bmatrix}= \begin{bmatrix}a & b \\ c & d\end{bmatrix}\begin{bmatrix} 0 & 1 \\ 1 & 0\end{bmatrix}[/tex]

Multiply those, set corresponding term equal, and see what you get.
 
  • #4
Thanks guys.

Anyway I just did my linear exam today so hopefully I never have to see linear ever again!
 

FAQ: Understanding Basis for Solving Linear Algebra Problems

Why is finding a basis important in linear algebra?

Finding a basis is important because it allows us to represent vectors and matrices in a more simplified form. It also helps us to understand the structure and properties of vector spaces, which are essential in many areas of mathematics and science.

What is the process for finding a basis?

The process for finding a basis involves identifying a set of linearly independent vectors that span the vector space. This can be done through various methods, such as elimination or substitution. Once a set of linearly independent vectors is found, it can be used to form a basis for the vector space.

What are the challenges in finding a basis?

One of the main challenges in finding a basis is ensuring that the vectors are linearly independent. This can be difficult to determine, especially for larger matrices. Another challenge is that there may be multiple possible bases for a given vector space, so it is important to choose a basis that is most suitable for the specific problem at hand.

Can a basis be found for any vector space?

Yes, a basis can be found for any vector space. This is because a vector space, by definition, must have a set of vectors that are linearly independent and span the space. However, finding a basis for some vector spaces may be more difficult than others.

How can I check if a set of vectors is a basis?

To check if a set of vectors is a basis, you can use the definition of a basis which states that the vectors must be linearly independent and span the vector space. This can be done by performing row operations on a matrix formed by the vectors and checking if it can be reduced to an identity matrix. If it can, then the vectors are linearly independent and form a basis for the vector space.

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