- #1
Xcellerator
- 8
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Ok, I am having some trouble with the maths regarding Bohr Theory. I understand that the orbit radius is
r=n^2xa0
where a0=0.0529
and that the wavelength for an electron with l=0 (circular orbit), is
λ=2∏r
so for n=1, λ=6.28a0.
So, following the same maths, for n=2, I get λ=2x∏x2^2=8∏a0.
However, according to http://hyperphysics.phy-astr.gsu.edu/hbase/bohr.html#c5, The answer is 4∏a0, which means that n is not squared.
Can anyone please explain whether or not n is squared to work out the orbital radius?
r=n^2xa0
where a0=0.0529
and that the wavelength for an electron with l=0 (circular orbit), is
λ=2∏r
so for n=1, λ=6.28a0.
So, following the same maths, for n=2, I get λ=2x∏x2^2=8∏a0.
However, according to http://hyperphysics.phy-astr.gsu.edu/hbase/bohr.html#c5, The answer is 4∏a0, which means that n is not squared.
Can anyone please explain whether or not n is squared to work out the orbital radius?