Understanding Capacitor Energy Storage: Clarifying Charge and Energy Units

In summary, the capacitor holds a charge of 1200 joules on each plate. If the voltage is applied to the capacitor, the charge will be separated between the positive and negative plates. The capacitance of the capacitor is calculated to be 1200 farads.
  • #1
leelsund
4
0
I guess this is a simple question and I can't find clarification on it any where

If the total charge on each plate of a parallel plate capacitor is 1200 joules then is the total energy stored in that capacitor 2400 joules. Lol might seem dumb but I just want to make sure this was correct

Thanks
 
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  • #2


leelsund said:
the total charge on each plate of a parallel plate capacitor is 1200 joules then
Charge is measured in units of coulombs, not joules.
 
  • #3


DaleSpam said:
Charge is measured in units of coulombs, not joules.

k then does the charge on each plate = total charge

so 1200 on one plate 1200 on the other = 2400
 
  • #4


Capacitor charge Q is defined so that there is charge separation with +Q on the positive plate and also -Q on the negative plate, when we say that the capacitor voltage is V=Q/C and the energy stored is (1/2)CV^2.

(Note that a total for +Q and -Q would always be zero.)
 
Last edited:
  • #5


mikelepore said:
Capacitor charge Q is defined so that there is charge separation with +Q on the positive plate and also -Q on the negative plate, when we say that the capactor voltage is V=Q/C and the energy stored is (1/2)CV^2.

(Note that a total for +Q and -Q would always be zero.)

total energy stored in a capacitor is split between the 2 plates. So say the capacitor stores 2 joules of energy does each plate hold 1 joule of charge.
 
  • #6


Don't think of each plate holding half of the energy. Think of the energy being in the fact that +Q and -Q are attracted to each other but not allowed to move toward each other because of the insulation in the spacing.
 
  • #7


mikelepore said:
Don't think of each plate holding half of the energy. Think of the energy being in the fact that +Q and -Q are attracted to each other but not allowed to move toward each other because of the insulation in the spacing.

The question I have is a parallel plate capacitor holds a charge of 1200 joules on each plate. It has a potential difference of 110 volts applied to it what is the capacitance of the capacitor in farads
 
  • #8


What DaleSpam said above. If the question says "a charge of 1200 joules" the question is incorrectly worded. I would ask the writer of the question if they mean "a charge of 1200 coulombs." If they say yes, then Q is 1200 coulombs.

I have never heard anyone refer to energy per plate.
 

FAQ: Understanding Capacitor Energy Storage: Clarifying Charge and Energy Units

What is a capacitor?

A capacitor is a passive electronic component that stores electrical energy in the form of an electric field. It is made up of two conductive plates separated by an insulating material called a dielectric.

How does a capacitor store energy?

A capacitor stores energy by accumulating opposite charges on its two plates. When a voltage is applied, electrons are drawn to one plate, leaving a positive charge on the other plate. The electric field between the plates stores the energy.

What is the unit of measurement for capacitance?

The unit of measurement for capacitance is the farad (F). However, capacitors are usually measured in smaller units such as microfarads (μF) or picofarads (pF).

How does the energy stored on a capacitor change with capacitance and voltage?

The energy stored on a capacitor is directly proportional to the capacitance and the square of the voltage applied. This means that increasing the capacitance or the voltage will result in a higher energy storage capacity.

How is the energy on a capacitor released?

The energy stored on a capacitor can be released by connecting a load to the two plates. This allows the stored charges to flow through the circuit, providing electrical energy to power the load. The rate at which the energy is released depends on the capacitance and the voltage of the capacitor.

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