- #1
vidit jain
- 18
- 1
hey, so I learned about capacitors and one particular detail about capacitors that is stressed upon is that the field of a capacitor is contained between the plates of it( assuming the field from the edge of plate to be very small). So my question was that when we short a capacitor, why does the charge from one plate flow to the other to balance it out when there is no electric field in the wire?if there is, what creates the field?
Please do not use the potential argument as my understanding of physics tells me that potential follows field and not vice versa.
I had thoughts that the existing charges on the plate pushes the charge 'out of the plate' due to repulsive forces but I don't think this explanation is correct as charge doesn't flow when just one plate of a capacitor is earthed.
Thank you
Edit 1.
Consider the diagram. When a wire is connected on the outside of the capacitor ie it lies in region A or C, how is an electric field set up in the wire which drives a current to neutralise the charge on the plates?
Please do not use the potential argument as my understanding of physics tells me that potential follows field and not vice versa.
I had thoughts that the existing charges on the plate pushes the charge 'out of the plate' due to repulsive forces but I don't think this explanation is correct as charge doesn't flow when just one plate of a capacitor is earthed.
Thank you
Edit 1.
Consider the diagram. When a wire is connected on the outside of the capacitor ie it lies in region A or C, how is an electric field set up in the wire which drives a current to neutralise the charge on the plates?
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