- #1
eclayj
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Homework Statement
Determine if the sets A, B, C, and D satisfy the following proposition (p) for the set S:
Homework Equations
p: for all ε > 0, ∃ x [itex]\in[/itex] S such that x < ε
A = {1/n : n [itex]\in[/itex] Z+}
B = {n : n ε Z+}
C = A [itex]\cup[/itex] B
D = {-1}
The Attempt at a Solution
I am looking for a little help in reading/interpreting the mathematical statements with double quantifiers and "ε," I have always had terrible trouble understanding what these mean (I have never quite understood the formal definition of a limit for example).
Let me attempt to explain how I understand proposition p, for example, and how it would relate to set A, B, C, and D. Then please tell me if I am off the mark.
For p, after I read it a few times I interpreted it as a condition requiring the set to contain at least one element, x, that is less than some number ε, where that number ε can be made arbitrarily close to 0. The only set I could visualize that would allow for this is a set that contains elements which get arbitrarily close to 0 (if the set does not contain negative numbers), or a set which contains negative numbers.
A satisfies this condition because the members of its set approach 0 as n approaches infinity. So, no matter what epsilon you choose, you can always find a smaller x value in set A
B does not satisfy this condition, because you can choose 0 < ε < 1, but the elements of this set are restricted to whole numbers, and therefore all elements in set B [itex]\geq[/itex] 1
A [itex]\cup[/itex] B satisfy p b/c it includes set A, the elements of which approach 0 as n approaches infinity (i.e., get infinitely close to 0).
Finally set D trivially satisfies condition p b/c condition p restricts the choice of ε > 0, and the only element of set D is < 0