- #1
KLscilevothma
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If an electric field is due to 2 parallel plate conductors carrying equal and opposite charges, which plate got the higher potential, positive one or negative one?
Electric potential = Q/(4*pi*ε*r)
If charge, Q is negative, electric potential is negative, does it mean that the negative plate has a lower potential than the positive one?
However in a battery, say a dry cell, negative terminal has higher potential then the positive one. Hm... I'm a little bit confused.
Electric potential = Q/(4*pi*ε*r)
If charge, Q is negative, electric potential is negative, does it mean that the negative plate has a lower potential than the positive one?
However in a battery, say a dry cell, negative terminal has higher potential then the positive one. Hm... I'm a little bit confused.