MHB Understanding how to do money problems?

  • Thread starter Thread starter sparater
  • Start date Start date
  • Tags Tags
    Money
AI Thread Summary
Family A borrowed 100 grams of gold from Family B in 1950 with a 7% annual interest rate, compounded yearly, and agreed to pay back half of the owed amount each January 1st. The discussion revolves around calculating the total gold Family A will eventually return, the amount paid back by March 2007, and determining when the loan will be fully repaid. Participants suggest breaking down the problem into manageable questions to identify the amounts owed and received over the years. The calculations involve understanding geometric series and compounding interest, with some confusion regarding specific factors used in the formulas. Clarification on the equations and variables is encouraged to solve the problem effectively.
sparater
Messages
3
Reaction score
0
4. In 1950, Family A borrowed 100 grams of gold from Family B with an
interest (in gold) of 7%, compounded annually at the end of the year.
Every January 1st, Family A pays o half of what it owes Family B.
(a) How much gold will Family A eventually give back to Family B?
(b) How much gold was paid back by March 2007?
(c) When will Family A be done paying this loan?
 
Mathematics news on Phys.org
sparater said:
4. In 1950, Family A borrowed 100 grams of gold from Family B with an
interest (in gold) of 7%, compounded annually at the end of the year.
Every January 1st, Family A pays o half of what it owes Family B.
(a) How much gold will Family A eventually give back to Family B?
(b) How much gold was paid back by March 2007?
(c) When will Family A be done paying this loan?

Welcome to MHB, sparater! :)

Perhaps you can indicate where you are stuck?

Let me start by giving a couple of hints in the form of questions.

How much gold will family A owe by December 31st, 1950?
How much gold will family A owe by January 1st, 1951?
How much gold will family B have received by January 1st, 1951?
How much gold will family A owe by December 31st, 1951?
How much gold will family A owe by January 1st, 1952?
How much gold will family B have received by January 1st, 1952?

See a pattern?
 
Thanks for the quick reply!

I am unsure how to start the problem. I don't know what equation and what variables to use!
 
sparater said:
Thanks for the quick reply!

I am unsure how to start the problem. I don't know what equation and what variables to use!

Let's worry about equations and variables later.
Perhaps you can start with my suggested questions?

Or if you really want variables, let's pick $n$ for the number of years since January 1st, 1950, $A$ for the amount that family A owes in any year, and $B$ for the amount family B has received in total in any year.
 
I understand that this would be a geometric series problem along with compounding.

I have :

Sum from 0 to infinity of (.465(100*.535^n))
 
sparater said:
I understand that this would be a geometric series problem along with compounding.

I have :

Sum from 0 to infinity of (.465(100*.535^n))

Yes, the total that B receives would be a geometric series.
But... where did the factor .465 come from?

Anyway, is there anything in particular that you need help with?
I prefer not to guess as that tends to be counter productive.
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
Back
Top