Understanding Lenz's Law: Which End of the Resistor is Positive?

[Dart82]

Homework Statement

Review the following drawing.

The semicircular piece of wire rotates through half a revolution in the direction shown, starting from the position indicated in the drawing. Which end of the resistor, the left or the right end, is positive?
a. neither -- there is no induced emf
b. the left end
c. the right end

The Attempt at a Solution

i chose "C. the right end"
Ok the loop will initially move away from the field as it turns (decreasing the field and flux), but it will then move toward the field increasing it (and the flux) into the page. to oppose this, a field directed out of the page is induced by a Counter Clock-Wise current. Current will flow from negative to positive regions.

 

[Nate810]

since the current is CCW and the right side of the resistor is closer to the field, the right side will be positive.

 

[m2003]

So the right side must be positive.

I would like to clarify that Lenz's Law is a fundamental principle in electromagnetism that states that an induced current in a conductor will flow in a direction that opposes the change in magnetic flux that caused it. In this scenario, the semicircular wire is rotating through the magnetic field, causing a change in flux. According to Lenz's Law, the induced current will flow in a direction that opposes this change, and therefore the right end of the resistor will be positive. This is because the induced current will flow in the direction that creates a magnetic field that opposes the original field, which is into the page. This means that the current will flow from the negative end of the resistor (left end) to the positive end (right end). Therefore, the right end of the resistor is positive in this scenario.