- #1
Radiohannah
- 49
- 0
Hello there!
May I ask:
I am learning about the conservation of lepton number. I understand that the lepton number is composed of different sorts of lepton number,
[tex] L_{\mu}[/tex] and [tex]L_{\tau}[/tex] and [tex]L_{e}[/tex].
And these are conserved in all interactions.
I am confused however about the lepton number for anti-particles. Are the lepton numbers negative for anti-particles?
Because in the muon decay;
[tex] \mu^{-} \rightarrow e^{-} + \overline{\nu_{e}} + \nu_{\mu}[/tex]
I can see that [tex]L_{\tau}[/tex] is conserved (0) and [tex] L_{\mu}[/tex] is conserved, but [tex]e^{-}[/tex] would have [tex]L_{e}=1[/tex] and then [tex]\overline{\nu_{e}}[/tex] would have [tex]L_{e}= -1[/tex] which isn't conserved.
:-S
Cheers
May I ask:
I am learning about the conservation of lepton number. I understand that the lepton number is composed of different sorts of lepton number,
[tex] L_{\mu}[/tex] and [tex]L_{\tau}[/tex] and [tex]L_{e}[/tex].
And these are conserved in all interactions.
I am confused however about the lepton number for anti-particles. Are the lepton numbers negative for anti-particles?
Because in the muon decay;
[tex] \mu^{-} \rightarrow e^{-} + \overline{\nu_{e}} + \nu_{\mu}[/tex]
I can see that [tex]L_{\tau}[/tex] is conserved (0) and [tex] L_{\mu}[/tex] is conserved, but [tex]e^{-}[/tex] would have [tex]L_{e}=1[/tex] and then [tex]\overline{\nu_{e}}[/tex] would have [tex]L_{e}= -1[/tex] which isn't conserved.
:-S
Cheers