- #36
Reckoner
- 45
- 0
For all $x < 0,$ $f(x) = -1.$ Since we are taking the left-handed limit ($h$ is approaching 0 from the left), we are dealing with $h < 0.$ Similarly, for the right-handed limit we are looking at where $h > 0$ so that $f(h) = 1.$Rido12 said:Can someone explain to me the above? Like how did f(h) become -1?