- #1
StatMechGuy
- 223
- 2
I've been doing some reading on QCD, and I keep running into the notion of "massless quarks". Are they massless in the sense that if you look at
[tex]
E = \pm \sqrt{p^2 + m^2}
[/tex]
the [tex]p^2[/tex] term dominates and [tex]E \sim p[/tex] or is this something completely different?
[tex]
E = \pm \sqrt{p^2 + m^2}
[/tex]
the [tex]p^2[/tex] term dominates and [tex]E \sim p[/tex] or is this something completely different?