- #1
zak8000
- 74
- 0
what does normalization mean?
for example say i have the guassian input as :
[tex]A(0,T) = \sqrt{Po}*exp(-T^2/2To^2) [/tex]
then we can normalize it by defining t=T/To and [tex]A(z,T) = \sqrt{Po}U(z,t)[/tex]
Po= peak power t= normalized to the input pulse width To. if the peak of the pulse is (arbirtarily) set in t=T=0, we have U(z=0,t=0)=1 . with these notations both t and U are now dimensionless and the normalized form the gaussin input can be written as:
[tex]U(0,t) = exp(-t^2/2)[/tex]
i am just a bit confused as to what this means. in the normalized form the peak power dissappears and why is the normalized form uselfull is it because it makes calculations easier?
for example say i have the guassian input as :
[tex]A(0,T) = \sqrt{Po}*exp(-T^2/2To^2) [/tex]
then we can normalize it by defining t=T/To and [tex]A(z,T) = \sqrt{Po}U(z,t)[/tex]
Po= peak power t= normalized to the input pulse width To. if the peak of the pulse is (arbirtarily) set in t=T=0, we have U(z=0,t=0)=1 . with these notations both t and U are now dimensionless and the normalized form the gaussin input can be written as:
[tex]U(0,t) = exp(-t^2/2)[/tex]
i am just a bit confused as to what this means. in the normalized form the peak power dissappears and why is the normalized form uselfull is it because it makes calculations easier?