- #1
honestrosewater
Gold Member
- 2,143
- 6
(keeping in mind some conventional symbols are here written out in words...)
For
n * X + M = y
where
n is in N,
X is in Z and nonnegative,
M is in Z and nonnegative and less than n,
and y is, of course, defined by n, X, and M
sequence
M_i = (n * X + i) [X = (0, 1, 2, ...)]
where i takes, in turn, each value of M for some n (or for each n, or when n is constant, how should I say this?). So when n = 3, then M = {0, 1, 2} and M_i denotes collectively the sequences
M_0 = ( n * X + 0 ) [X = ( 0, 1, 2, ... )]
M_1 = ( n * X + 1 ) [X = ( 0, 1, 2, ... )]
M_2 = ( n * X + 2 ) [X = ( 0, 1, 2, ... )],
i.e, there is a sequence for each value, i, that M takes.
Does a better way of saying this jump out at anyone?
Any help will be greatly appreciated, as I am working on my own and don't know how this is conventionally expressed.
Rachel
For
n * X + M = y
where
n is in N,
X is in Z and nonnegative,
M is in Z and nonnegative and less than n,
and y is, of course, defined by n, X, and M
sequence
M_i = (n * X + i) [X = (0, 1, 2, ...)]
where i takes, in turn, each value of M for some n (or for each n, or when n is constant, how should I say this?). So when n = 3, then M = {0, 1, 2} and M_i denotes collectively the sequences
M_0 = ( n * X + 0 ) [X = ( 0, 1, 2, ... )]
M_1 = ( n * X + 1 ) [X = ( 0, 1, 2, ... )]
M_2 = ( n * X + 2 ) [X = ( 0, 1, 2, ... )],
i.e, there is a sequence for each value, i, that M takes.
Does a better way of saying this jump out at anyone?
Any help will be greatly appreciated, as I am working on my own and don't know how this is conventionally expressed.
Rachel