Understanding Point Masses: Key Concepts and Limitations for A Level Physics

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In summary: I do not have a specific answer and was hoping for a general answer. Sorry if I wasn't clear. Your answer is helpful
  • #1
Faiq
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"Understand that, for a point outside a uniform sphere, the mass of the sphere can be considered a point mass."
This is one of the "learning outcomes" in the A level Course. Here are my questions related to it.
1.) What is meant by point masses? (A definition will do)
2.) Why do we consider point masses? What's the problem with dealing a uniform spherical objects as normal spherical objects?
3.) What are the limitations for this consideration? When this consideration can't be used?
4.) They are dealing with "point outside a uniform sphere". Why is the consideration not suitable when the point is inside the uniform sphere?
 
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  • #2
Faiq said:
"Understand that, for a point outside a uniform sphere, the mass of the sphere can be considered a point mass."
This is one of the "learning outcomes" in the A level Course. Here are my questions related to it.
1.) What is meant by point masses? (A definition will do)
A point. That has mass.
2.) Why do we consider point masses? What's the problem with dealing a uniform spherical objects as normal spherical objects?
Do you have any IDEA how complex the math would be if you did not consider it as a point mass?
3.) What are the limitations for this consideration? When this consideration can't be used?
It can be used exactly when the statement you quoted says it can be used.
4.) They are dealing with "point outside a uniform sphere". Why is the consideration not suitable when the point is inside the uniform sphere?
Only the part of the mass inside the radius of the object under consideration can be counted as the point mass, not the entire sphere including the part that has a larger radius.
 
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  • #3
Faiq said:
2.) Why do we consider point masses? What's the problem with dealing a uniform spherical objects as normal spherical objects?
There isn't a problem, it is just simpler math. For example, to calculate the gravitational acceleration a distance of ##r## away from a uniform spherical mass of radius ##R## (with ##R<r##) and mass ##M=\rho \frac{4}{3} \pi R^3##, you can either calculate:
$$a=GM/r^2$$
or you can calculate (assuming I even set up the math correctly)
$$a= \int_{-\sqrt{R^2-x^2-y^2}}^{\sqrt{R^2-x^2-y^2}} \int_{-\sqrt{R^2-x^2}}^{\sqrt{R^2-x^2}} \int_{-R}^R \rho G \frac{(r-x,y,z)}{\left( (r-x)^2+(y)^2+(z)^2 \right)^{3/2}} \; dx \, dy \, dz $$
The answer is the same.
 
  • #4
Dale said:
There isn't a problem, it is just simpler math. For example, to calculate the gravitational acceleration a distance of ##r## away from a uniform spherical mass of radius ##R## (with ##R<r##) and mass ##M=\rho \frac{4}{3} \pi R^3##, you can either calculate:
$$a=GM/r^2$$
or you can calculate (assuming I even set up the math correctly)
$$a= \int_{-\sqrt{R^2-x^2-y^2}}^{\sqrt{R^2-x^2-y^2}} \int_{-\sqrt{R^2-x^2}}^{\sqrt{R^2-x^2}} \int_{-R}^R \rho G \frac{(r-x,y,z)}{\left( (r-x)^2+(y)^2+(z)^2 \right)^{3/2}} \; dx \, dy \, dz $$
The answer is the same.
Can you also answer the other questions I mentioned here?
 
  • #5
Faiq said:
4.) They are dealing with "point outside a uniform sphere". Why is the consideration not suitable when the point is inside the uniform sphere?

You've got to work out the answer to 4) for yourself!
 
  • #6
Faiq said:
Can you also answer the other questions I mentioned here?
What did you not find satisfactory about the answers I already gave you? Do you think they are wrong? Are they incomplete?
 
  • #7
Faiq said:
Can you also answer the other questions I mentioned here?
I don't have anything to add to the excellent response from @phinds
 
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  • #8
Faiq said:
"Understand that, for a point outside a uniform sphere, the mass of the sphere can be considered a point mass."
This is one of the "learning outcomes" in the A level Course. Here are my questions related to it.
1.) What is meant by point masses? (A definition will do)
A point mass in this context is the sphere treated as if all of its mass were located at a single point at its centre.
2.) Why do we consider point masses? What's the problem with dealing a uniform spherical objects as normal spherical objects?
Someone has already done the math and it works out that, to a body outside the sphere, the contributions to gravity of all the matter in the uniform sphere are equivalent to the contribution to gravity of a point mass having the same mass as the sphere but located at the centre of the sphere. See Dale's post above.
3.) What are the limitations for this consideration? When this consideration can't be used?
I am not sure what this question is asking. The mass of the sphere must be uniformly distributed throughout (i.e. uniform density).
4.) They are dealing with "point outside a uniform sphere". Why is the consideration not suitable when the point is inside the uniform sphere?
Consider a point located a distance s from the centre of the sphere but inside the sphere (ie. at a radius s < R, where R is the sphere radius). Newton, using calculus, showed that the mass that is located within the sphere at a radius greater than s (ie. a distance r from the centre where s < r ≤ R) does not affect the gravitational field at s. Only the mass within the sphere at a radius ≤ s contributes.

AM
 
  • #9
phinds said:
What did you not find satisfactory about the answers I already gave you? Do you think they are wrong? Are they incomplete?
No I don't consider them incomplete. I was expecting an answer which I can write in examination. If I wrote "a point that has mass" I would be deducted marks for incomplete definition or some sort of those things.
 
  • #10
Andrew Mason said:
I am not sure what this question is asking. The mass of the sphere must be uniformly distributed throughout (i.e. uniform density).
Consider a point located a distance s from the centre of the sphere but inside the sphere (ie. at a radius s < R, where R is the sphere radius). "Newton, using calculus, showed that the mass that is located within the sphere at a radius greater than s (ie. a distance r from the centre where s < r ≤ R) does not affect the gravitational field at s. Only the mass within the sphere at a radius ≤ s contributes."

AM
About your first question, I was asking when is this consideration not suitable. Example what are situations in which using point masses would give me wrong answer.
And can you please explain the sentences in quotation marks?
 
  • #11
Faiq said:
No I don't consider them incomplete. I was expecting an answer which I can write in examination. If I wrote "a point that has mass" I would be deducted marks for incomplete definition or some sort of those things.
Then use the more complete answer given by Andrew. It says the same thing really, but it's more elegant
 
  • #12
phinds said:
Then use the more complete answer given by Andrew.
It says the same thing really, but it's more elegant but on the other hand it answers a more extensive question than what you asked. My answer is exactly the right answer for your exact question.
 
  • #13
Faiq said:
About your first question, I was asking when is this consideration not suitable. Example what are situations in which using point masses would give me wrong answer.
And can you please explain the sentences in quotation marks?
The Wikipedia article gives a pretty thorough explanation of this.

AM
 

FAQ: Understanding Point Masses: Key Concepts and Limitations for A Level Physics

What is a point mass?

A point mass is a hypothetical object that has a mass but occupies no physical space. It is often used in physics and other sciences as a simplified model for objects that are very small or have a uniform density.

How is a point mass different from a regular mass?

A regular mass has physical dimensions and occupies space, whereas a point mass does not. Additionally, a regular mass can have varying densities, while a point mass is assumed to have a uniform density throughout.

How do point masses affect gravitational fields?

Point masses have a significant influence on gravitational fields. They attract each other according to the universal law of gravitation, which states that the force between two point masses is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

Can point masses be used to represent real-world objects?

Yes, point masses can be used as a simplified representation of real-world objects in certain scenarios. For example, in celestial mechanics, planets and stars are often modeled as point masses because their physical dimensions are negligible compared to their mass.

Are there any limitations to using point masses in scientific models?

Yes, there are limitations to using point masses in scientific models. They are most useful in situations where the objects being studied are very small or have a uniform density. In real-world scenarios, most objects have varying densities and physical dimensions, so using point masses may not accurately represent their behavior.

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