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Your answer looks right to me.Miike012 said:I posted the question and the answer from the book inside the paint document.
My question is why is the answer not...
Δx = 3-1 = 2m
ΔE = 200-0 = 200V/m
ΔV = -(Area under E vs x graph) = -Δx*ΔE/2 = -200 V
Potential difference, also known as voltage, is the difference in electric potential energy between two points in an electric circuit. It is measured in volts (V) and can be thought of as the force that drives the flow of electric current.
Potential difference is calculated by dividing the change in electric potential energy (measured in joules, J) by the amount of charge (measured in coulombs, C) that moves through the circuit. This can be represented by the formula V = ΔE/q.
Potential difference is measured in units of volts (V), which is equivalent to one joule per coulomb (J/C).
Potential difference is directly related to electric current, as it is the driving force behind the flow of current in a circuit. A higher potential difference will result in a higher current, while a lower potential difference will result in a lower current.
The main factors that affect potential difference are the amount of charge (measured in coulombs) and the distance between the two points in the circuit. Other factors such as resistance and the type of material used in the circuit can also affect potential difference.