- #1
jk22
- 731
- 24
Suppose we have 2n binary choices. Then the probability of having the same number of results is :
C(2n,n)/2^(2n) ?
I don't know if this is true, since for the case n=1million, we have a probability as high as 1/2000, which seems quite important ?
C(2n,n)/2^(2n) ?
I don't know if this is true, since for the case n=1million, we have a probability as high as 1/2000, which seems quite important ?