Understanding Scattered Radiation in Photon Beams

In summary, the attenuation coefficient of a beam of photons is known. If I'm not wrong, this formula tells us the number of photons that passed through the material of thickness x without interacting with it (), but it does not tell us the "real" total number of photons that we should expect to see beyond this material () given by the sum of the first ones and the "scattered radiation". My question is about what do we mean with "scattered radiation"?.
  • #1
eneacasucci
55
14
TL;DR Summary
scattered radiation of photons when passing through a material
Consider a source emitting a beam of photons. These photons pass through x thickness of material. The attenuation coefficient of the beam \mu is known.
We can write this formula
1683192752250.png

1683189958516.png

If I'm not wrong, this formula tells us the number of photons that passed through the material of thickness x without interacting with it (
1683190403717.png
), but it does not tell us the "real" total number of photons that we should expect to see beyond this material (
1683190424672.png
) given by the sum of the first ones and the "scattered radiation".
My question is about what do we mean with "scattered radiation"?.
This is what I think about: "scattered radiation" are the photons resulting from the interaction of the primary beam with matter, that can happen in these ways:
1)photoelectric effect: with characteristic x-ray emission
2)Compton effect: in which the original photon loses energy, which is transferred to an electron
3)pair production: in which additional photons may be emitted if positron-electron annihilation occurs
4)coherent scattering: photon undergoes deflection but does not lose energy


Are these photons (1,2,3,4) the ones constituting the so-called "scattered radiation"? is there something else?P.S. To get a correct estimate of the photons passing through the material, thus also considering scattered photons, I should add a correction term, how is it estimated?
 
Last edited:
Physics news on Phys.org
  • #2
There is also possibility of no interaction at all, right?
 
  • Like
Likes eneacasucci
  • #3
malawi_glenn said:
There is also possibility of no interaction at all, right?
Yes I think so, as I've written, the number of photons that pass through the material without interacting should be given by this formula
1683192734489.png
 
  • #4
That formula does not take into account "rescattering" becuase it is assumed that the in comming radiation is monoenergetic. Keep in mind that ##\mu## depends on the photon energy. For a more detailed treatment you need to perform simulations use e.g. Geant4 software
 
  • #5
@eneacasucci, could you please use Latex for your equations instead of embedding images? For example ##N(x)=N_0e^{-\mu x}## - there’s a Latex guide linked right below where you type posts/replies.
 
  • Like
Likes eneacasucci
  • #6
malawi_glenn said:
That formula does not take into account "rescattering" becuase it is assumed that the in comming radiation is monoenergetic. Keep in mind that ##\mu## depends on the photon energy. For a more detailed treatment you need to perform simulations use e.g. Geant4 software
yes sure, ##\mu## depends on the energy of the photon.
Could I ask if it is possible to have an answer for the green questions in the original post? :) thank you so much for your time
 
Last edited:
  • Like
Likes vanhees71
  • #7
Nugatory said:
@eneacasucci, could you please use Latex for your equations instead of embedding images? For example ##N(x)=N_0e^{-\mu x}## - there’s a Latex guide linked right below where you type posts/replies.
Unfortunately I can't edit my original post but I'll try to write everything in latex in future messages and posts, sorry
 
  • Like
Likes berkeman
  • #8
eneacasucci said:
Yes I think so, as I've written, the number of photons that pass through the material without interacting should be given by this formula
1683192734489-png.png
This follows from assuming that any "scattering" removes the particle from the incident beam, never to be seen again. This is often a good approximation for open geometries and collimated beams. Also it is very easy to apply.
Particles being returned to the beam after repeat scattering are rare although some devices (lasers for instance) rely on this effect , so you need to understand the system. These problems are typically much more difficult to calculate.
 
  • Like
Likes vanhees71 and eneacasucci
  • #9
eneacasucci said:
Unfortunately I can't edit my original post but I'll try to write everything in latex in future messages and posts, sorry
That's good enough, no problem.
 

FAQ: Understanding Scattered Radiation in Photon Beams

What is scattered radiation in photon beams?

Scattered radiation refers to the deflection of photons from their original trajectory as they interact with matter. This scattering can occur due to various processes, such as Compton scattering, where photons collide with electrons, resulting in a change of direction and energy of the photons.

Why is understanding scattered radiation important in medical imaging?

Understanding scattered radiation is crucial in medical imaging because it can degrade image quality and increase the dose to non-target tissues. By comprehending how photons scatter, medical professionals can implement techniques to minimize scatter, thereby improving image clarity and reducing unnecessary radiation exposure to patients.

How can scattered radiation be minimized in photon beam applications?

Scattered radiation can be minimized through several methods, such as using collimators to narrow the beam, applying anti-scatter grids to absorb scattered photons, and optimizing beam energy and angles. Additionally, advanced imaging techniques like digital subtraction angiography can reduce the impact of scatter.

What role does Compton scattering play in scattered radiation?

Compton scattering is a significant contributor to scattered radiation in photon beams. It occurs when a photon collides with a loosely bound outer electron, resulting in the ejection of the electron and a deflected photon with reduced energy. This process is predominant in the diagnostic energy range and significantly affects image quality and radiation dose distribution.

How is scattered radiation measured and quantified?

Scattered radiation is measured using detectors such as ionization chambers, scintillation detectors, or semiconductor detectors. Quantification involves determining the scatter fraction, which is the ratio of scattered radiation to the total detected radiation. This helps in assessing the extent of scatter and implementing corrective measures in imaging and treatment planning.

Similar threads

Replies
21
Views
2K
Replies
1
Views
2K
Replies
4
Views
948
Replies
2
Views
2K
Replies
5
Views
4K
Replies
25
Views
11K
Replies
52
Views
5K
Replies
8
Views
3K
Back
Top