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Dx
I am curious to know that if a mass on a spring undergoes SHM. when the mass is at its MAX displacement from equilibrium, its instantaneous velocity is what?
is it zero!
can someone explain?
Dx
is it zero!
can someone explain?
Dx
SHM stands for Simple Harmonic Motion. It is a type of periodic motion where a body moves back and forth around a central equilibrium position.
The velocity of a mass on a spring at maximum displacement is equal to the product of the amplitude and the angular frequency. This can be represented by the equation v = Aω, where v is the velocity, A is the amplitude, and ω is the angular frequency.
The velocity of a mass on a spring at maximum displacement is affected by the amplitude of the oscillation, the mass of the object, and the spring constant. Additionally, the presence of any external forces or damping can also affect the velocity.
The velocity of a mass on a spring changes over time in a sinusoidal manner. It starts at its maximum value at the equilibrium position, decreases to zero at the maximum displacement, reaches its minimum value at the opposite equilibrium position, and then returns to its maximum value at the equilibrium position again.
In SHM, the velocity and acceleration are always perpendicular to each other. The velocity is at its maximum value when the acceleration is zero, and vice versa. This relationship can also be represented by the equation a = -ω²x, where a is the acceleration, ω is the angular frequency, and x is the displacement from the equilibrium position.