- #1
tmt1
- 234
- 0
Given than $n > 1$, then $\sin\left({\frac{1}{n^2}}\right) > 0$, but I'm not sure why that is.
I get that a sin function in the first quadrant will yield a positive result, but I'm not sure why it's in the first quadrant in the first place. Would $\frac{1}{n^2}$ be in degrees in this case, in which case, since it's less than 1 it would be in the first quadrant. That makes sense, but I'm not sure how to know that $n$ would be notated in degrees.
I get that a sin function in the first quadrant will yield a positive result, but I'm not sure why it's in the first quadrant in the first place. Would $\frac{1}{n^2}$ be in degrees in this case, in which case, since it's less than 1 it would be in the first quadrant. That makes sense, but I'm not sure how to know that $n$ would be notated in degrees.