Understanding Stopping Distance for an Alfa Romeo

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The discussion focuses on calculating the stopping distance for an Alfa Romeo at different speeds based on the principle that stopping distance is proportional to the square of velocity. It begins with a reference point of 177 feet at 70 mph and seeks to determine the stopping distances at 35 mph and 125 mph. The original poster is unsure about the mathematical setup and whether to use a parabolic equation for the calculations. Additionally, the conversation briefly touches on Poiseuille's Law for gas flow through a pipe, indicating a need for further clarification on that topic. The thread highlights the importance of understanding proportional relationships in physics and mathematics.
Amel
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Ok so I have this problem and it seems pretty simple but I am not getting what its trying to say.

According to Car and Driver, an Alfa Romeo going 70 mph requires 177 feet to stop. Assuming that the stopping distance is proportional to the square of the velocity, find the stopping distance required by an Alfa Romeo going at 35 mph and at 125 mph.

How do you set this up, do I have to find an equation of a parabola whith the point (70, 177) and then find the others using it? The way its worded I am not sure can anyone confirm this or clerify it better for me?
 
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If two quantities are proportional to one other, then their quotient is a constant.
 
Thank you, I got it right.
 
Ok what about this one,

Poiseuille's Law gives the rate of flow, R, of a gas through a cylindrical pipe in terms of the radius of the pipe, r, for a fixed drop in pressure between the two ends of the pipe.

If R = 430 cm3/s in a pipe of radius 2 cm for a certain gas, find a formula for the rate of flow of that gas through a pipe of radius r cm.
 

Thread 'Area of Overlapping Squares'

Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?
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