Understanding Stress and Strain in Springs for Engineers

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  • Thread starter Dethrone
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In summary, the conversation discusses a problem involving a mass hitting a flange and making assumptions about its behavior. The two methods presented involve the use of Hooke's law and Young's modulus to calculate the energy transferred and the stress and strain of the materials involved. The links provided also give further information about the course and the difficulty of the problem presented.
  • #1
Dethrone
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  • #2
Rido12 said:
View attachment 3327

Have no clue... :(

What's this, AP physics or some such? (Wondering)

Anyway, to make sense of this, we'll need to make a couple of assumptions, which we may want to reexamine later.

Here are the assumptions I would make - at least at first:
  1. When the mass hits the flange, it remains in contact with the flange up to its maximum deflection.
  2. At all times, the force in the top section is equal to the force in the bottom section.

Hints:

Both sections will deform as per Hooke's law.
The spring constants are given by Young's modulus for low-alloy-steel.
The energy transferred by the mass to achieve maximum deflection, would be given by the kinetic energy of the mass.
 
  • #3
So I have two methods, not sure which was is right or wrong.

Method 1:

By conservation of energy:

$$mgh=0.5 \sigma_1^2 \frac{V_1}{E}+0.5 \sigma_2^2 \frac{V_2}{E}$$
$$T_1=T_2$$
$$\sigma_1^1A_1=\sigma_2^2A_2$$

Two equations, two unknowns.

Method 2:

http://skule.ca/courses/exams/custom/20099/CIV102_2009__1329360837.pdf

Number two on this document.

About this course...it is hard to explain. It's just a compilation of 3 undergraduate courses in 1. The final exam might give a good indication of what is covered:
http://skule.ca/courses/exams/bulk/20139/CIV102H1F_2013_STRUCTURES%20&%20MATERIALS-AN%20INTRODUCTION%20TO%20ENGINEERING%20DESIGN.PDF

I've been told that the problem set questions (such as this one) are much easier than the ones on the exam.
 
  • #4
Rido12 said:
By conservation of energy:

$$mgh=0.5 \sigma_1^2 \frac{V_1}{E}+0.5 \sigma_2^2 \frac{V_2}{E}$$
$$T_1=T_2$$
$$\sigma_1^1A_1=\sigma_2^2A_2$$

What do your symbols mean? (Wondering)

Btw, your second link seems to be broken.
 
  • #5
Starting with:
$$mgh=\frac{1}{2}\sigma_1\epsilon V_1+\frac{1}{2}\sigma_2\epsilon V_2$$

Where sigma is stress, and epsilon is strain. Now we know that strain = stress / Young's modulus, we can make the substitution to get the equation I got in my previous post.

The broken link is:
http://skule.ca/courses/exams/bulk/20139/CIV102H1F_2013_STRUCTURES%20&%20MATERIALS-AN%20INTRODUCTION%20TO%20ENGINEERING%20DESIGN.PDF
The URL doesn't work if you directly click on it, you have to copy + paste from editing my post
 
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FAQ: Understanding Stress and Strain in Springs for Engineers

What is stress and strain?

Stress and strain are two closely related concepts in mechanics. Stress refers to the force applied to an object per unit area, while strain refers to the resulting deformation or change in shape of the object.

How are stress and strain related?

Stress and strain are directly proportional to each other, meaning that as stress increases, so does strain. This relationship is described by Hooke's law, which states that the stress is equal to the product of the material's Young's modulus and the strain.

What is the difference between elastic and plastic deformation?

Elastic deformation is when a material is able to return to its original shape after the stress is removed, while plastic deformation is when the material permanently changes shape. Elastic deformation occurs within the elastic limit, while plastic deformation occurs beyond the elastic limit.

What is a spring constant?

A spring constant, also known as a force constant, is a measure of the stiffness of a spring. It is defined as the amount of force required to stretch or compress a spring by a certain distance. It can be calculated by dividing the applied force by the resulting change in length.

How does temperature affect stress and strain?

Temperature can affect the stress and strain of a material in several ways. For most materials, as temperature increases, the material becomes more ductile and can withstand greater stress before breaking. However, in some materials, such as metals, high temperatures can cause them to become weaker and more susceptible to deformation.

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