- #1
gboff21
- 50
- 0
If a baryon wavefunction is [itex]\Psi = \psi_{spatial} \psi_{colour} \psi_{flavour} \psi_{spin}[/itex],
and we consider the ground state (L=0) only.
We know that the whole thing has to be antisymmetric under the interchange of two quarks. We know that colour is antisymmetric (always colourless) and spatial is symmetric. Therefore, the combination of flavour and spin has to be symmetric.
That's fine, I understand that. However, I'm very uncertain about what the 'interchange of two quarks' actually means. Interchange how?
For the 'easy' example of |uuu>. How is the flavour symmetric?
Basically, what does it mean to be symmetric in the quark model?
and we consider the ground state (L=0) only.
We know that the whole thing has to be antisymmetric under the interchange of two quarks. We know that colour is antisymmetric (always colourless) and spatial is symmetric. Therefore, the combination of flavour and spin has to be symmetric.
That's fine, I understand that. However, I'm very uncertain about what the 'interchange of two quarks' actually means. Interchange how?
For the 'easy' example of |uuu>. How is the flavour symmetric?
Basically, what does it mean to be symmetric in the quark model?