Understanding the Convergence Product Theorem in Series Algebra

In summary, the conversation discusses the product convergence theorem for absolutely convergent series, and the search for similar ideas in other resources such as Knopp's book and Bromwich's book. The conversation also mentions Abel's theorem and the connection between Cauchy sequences and convergence. Finally, the conversation concludes with a comment on the usefulness of Google's book resource.
  • #1
thesaruman
14
0
While reading the section about algebra of series of Arfken's essential Mathematical Methods for Physicist, I faced an intriguing demonstration of the product convergence theorem concerning an absolutely convergent series [tex]\sum u_n = U[/tex] and a convergent [tex]\sum v_n = V [/tex] . The autor assured that if the difference
[tex]D_n = \sum_{i=0}^{2n} c_i - U_nV_n,[/tex]
(where [tex]c_i[/tex] is the Cauchy product of both series and [tex]U_n[/tex] and [tex]V_n[/tex] are partial sums) tends to zero as n goes to infinity, the product series converges.
The first thing that came in my mind was the Cauchy criterion for convergence, but then I remembered that i and j should be any integer. So I searched through all the net and my books, and didn't find any close idea.
Where should I search for this? Knopp?
 
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  • #2
Knopp's book would be one of my first two choices (if you are referring to his big treatise on series). The other is a similar book by Bromwich. I don't have my copy at home so can't give the exact name, but it too is very good.
 
  • #4
By Abel's theorem if the sum converges it must converge to UV. So this theorem just combines that with the theorem that if a sequence is Cauchy it must converge. I don't know what the i and j you speak of are. The Bromwich book mentioned by statdad is
An Introduction To The Theory Of Infinite Series (1908)
now back in print and downloadable at books.google.com
http://books.google.com/books?id=ZY...+of+Infinite+Series&ie=ISO-8859-1&output=html

see in Bromwich
Article 33 pages 81-84
 
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  • #5
Thank you very much, statdad and lurflurf. I think that I finally understood what the author wanted to say. The product of series presents us to a dramatically new form of seeing the "tails" of the series. By the way, interesting find this google's books. Sorry for my late reply.
 

FAQ: Understanding the Convergence Product Theorem in Series Algebra

What is the convergence product theorem?

The convergence product theorem, also known as the Cauchy product theorem, is a mathematical theorem that states that the product of two absolutely convergent series is also absolutely convergent. In other words, if two infinite series converge absolutely, then their product will also converge absolutely.

What is the significance of the convergence product theorem?

The convergence product theorem is an important tool in mathematics, as it allows us to manipulate and combine infinite series in a way that preserves their convergence. This is useful in many areas of mathematics, including calculus, analysis, and number theory.

How is the convergence product theorem proven?

The convergence product theorem can be proven using the Cauchy criterion for convergence, which states that a series converges if and only if the sum of its terms can be made arbitrarily small by choosing a large enough index. By applying this criterion to the product of two absolutely convergent series, we can show that the product series also converges absolutely.

What are the conditions for applying the convergence product theorem?

In order for the convergence product theorem to be applicable, the two series being multiplied must both converge absolutely. This means that the sum of the absolute values of their terms must be finite. If this condition is not met, the theorem does not hold.

Can the convergence product theorem be extended to more than two series?

Yes, the convergence product theorem can be extended to more than two series. This is known as the generalized convergence product theorem, and it states that the product of any finite number of absolutely convergent series is also absolutely convergent. However, the proof for this extended version is more complex and requires the use of mathematical induction.

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