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cr41g
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Question
Suppose an inertial frame of reference S’ moves at a constant velocity v in the
positive x-direction with respect to a second inertial frame S. The Lorentz
transformation from S to S’ for the x coordinate of displacement is given by:
x′ =γ (x − vt)
Write down a corresponding expression for the inverse transformation, i.e. from
S’ to S, giving x in terms of x’ and t’.
Use these two expressions to derive the Lorentz transformation equation for time:
t'=γ(t-vx/c^2)
I think I have the first part, I answered x =γ (x' + vt). But the second part I have no idea I have been looking online and even watching lectures on youtube.
Thanks in advance.
Suppose an inertial frame of reference S’ moves at a constant velocity v in the
positive x-direction with respect to a second inertial frame S. The Lorentz
transformation from S to S’ for the x coordinate of displacement is given by:
x′ =γ (x − vt)
Write down a corresponding expression for the inverse transformation, i.e. from
S’ to S, giving x in terms of x’ and t’.
Use these two expressions to derive the Lorentz transformation equation for time:
t'=γ(t-vx/c^2)
I think I have the first part, I answered x =γ (x' + vt). But the second part I have no idea I have been looking online and even watching lectures on youtube.
Thanks in advance.