Understanding the Math Behind coth(y) = x

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In summary, the conversation discusses the use of inverse hyperbolic functions in solving equations and understanding their properties. The formula $ coth(y) = x = \frac{{e}^{2y+1}}{{e}^{2y-1}}$ is used to extract the value of $y$ in terms of $x$, which is $\frac{1}{2}ln\frac{x+1}{x-1}$. The speaker expresses frustration in understanding the intuition behind inverse hyperbolic functions and asks for clarification on their purpose. The conversation ends with a request for a better understanding of hyperbolic and inverse hyperbolic functions.
  • #1
ognik
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This is one of those 'huh?' moments where I can follow what is said, but don't understand it at all.
From $ coth(y) = x = \frac{{e}^{2y+1}}{{e}^{2y-1}}, $ we extract: $
y=\frac{1}{2} ln \frac{x+1}{x-1} $.
I've looked at graphs and definitions online, I follow what is done (kind of swapping x and y) - but would like to understand the details instead of just parroting it.
So I tried: $\ln\left({x}\right) = \ln\left({{e}^{2y}+1}\right) - \ln\left({{e}^{2y}-1}\right) $ - and am stuck here...
 
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  • #2
I would begin with:

\(\displaystyle x=\frac{e^{2y}+1}{e^{2y}-1}\)

and solve for $e^{2y}$ first:

\(\displaystyle x\left(e^{2y}-1\right)=e^{2y}+1\)

\(\displaystyle e^{2y}(x-1)=x+1\)

\(\displaystyle e^{2y}=\frac{x+1}{x-1}\)

Can you proceed?
 
  • #3
Yes, more than enough, thanks muchly. Just frustrating that I sometimes can't see the bleedin' obvious ...:-(

Do you (or anyone) perhaps have a good way for me to get a lasting 'intuition' about what inverse hyperbolics are? I look at, for example, the well known sin x; it is periodic.

Then, it seems, sinh x is a reflection of sin x about the line y=x. It ends up not very dissimilar from sin x (I looked at 7. The Inverse Trigonometric Functions) , but with a limited range - it is not periodic?

Then arcsin x is again a reflection of sinh x about y=x. It looks closer to what sinx was (Inverse Hyperbolic Functions) , also not periodic?

But what do hyperbolic and inverse hyperbolic functions do - apart from causing me to see double after a while ...Sin is a wave, I can look at ripples in a pond etc. The others?
 

FAQ: Understanding the Math Behind coth(y) = x

1. What does the function coth(y) represent?

The function coth(y) is the hyperbolic cotangent of a number y. It is the ratio of the hyperbolic cosine of y to the hyperbolic sine of y.

2. How is coth(y) related to the function tanh(y)?

Coth(y) and tanh(y) are related by the formula coth(y) = 1/tanh(y). This means that they are reciprocals of each other.

3. How can I solve for y in the equation coth(y) = x?

To solve for y, you can use the inverse hyperbolic cotangent function or the natural logarithm. The inverse hyperbolic cotangent function is denoted by coth-1(x) and is equal to ln[(x+1)/(x-1)]. Therefore, y = coth-1(x) = ln[(x+1)/(x-1)].

4. What is the domain and range of coth(y)?

The domain of coth(y) is all real numbers except 0. The range of coth(y) is (-∞,-1) U (1,∞).

5. How is coth(y) used in real-world applications?

Coth(y) has various applications in fields such as physics, engineering, and finance. It is used to model phenomena such as heat transfer, electrical circuits, and stock market analysis. It can also be used to solve differential equations and calculate integrals.

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