- #1
Vibhor
- 971
- 40
Hello ,
This is a question related to an everyday activity .
My thinking - The base of the inclined plane is along the x-axis and it makes an angle θ with positive x-axis .We are looking from the +z axis .
There will be three forces acting on the person . Weight , normal(perpendicular to the plane) and friction(upwards along the plane) .
If a man does not lean forward and remains along a perpendicular to the plane then there would be an anticlockwise torque from friction about the COM .This unbalanced torque would cause instability .
But if the person is leaning forward , the line of action of normal force will not pass through the COM .A clockwise torque from normal about the COM will get balanced by an anticlockwise torque from friction resulting in stability .
Is my understanding correct . If not , please give a correct explanation and help me understand this .
Thanks
This is a question related to an everyday activity .
My thinking - The base of the inclined plane is along the x-axis and it makes an angle θ with positive x-axis .We are looking from the +z axis .
There will be three forces acting on the person . Weight , normal(perpendicular to the plane) and friction(upwards along the plane) .
If a man does not lean forward and remains along a perpendicular to the plane then there would be an anticlockwise torque from friction about the COM .This unbalanced torque would cause instability .
But if the person is leaning forward , the line of action of normal force will not pass through the COM .A clockwise torque from normal about the COM will get balanced by an anticlockwise torque from friction resulting in stability .
Is my understanding correct . If not , please give a correct explanation and help me understand this .
Thanks
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