Understanding the Proof of the Existence of Rational Numbers in Any Interval

In summary, the theorem states that in any interval (a,b), there is at least one rational number. This is proven by choosing a positive integer n large enough so that 1/n is smaller than the length of the interval, and then considering the multiples of 1/n. Similarly, there are an infinite number of irrational numbers in any interval by choosing a small enough irrational number and multiplying it by a large enough integer.
  • #1
3ephemeralwnd
27
0

Homework Statement


theorem: There is at least 1 rational # in any interval

Say a<b and let I = (a,b).

Let n be a positive integer so large that 1/n < b-a and consider the numbers k/n (where K is an integer). Then there will be a K such that k/n EI



I'm just having a bit of trouble understanding this proof, it just seems to lack a lot of.. explanation

I don't understand why n has to be a positive integer so large that 1/n<b-a .. and where does K come from?
 
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  • #2
Maybe it will help your understanding if I use numbers rather than variables. Let's say that a = 3/4 and b = 7/8, so I = (3/4, 7/8)

7/8 - 3/4 = 1/8, so let's take n = 9. Then 1/9 < 7/8 - 3/4.

Now consider the multiples of 1/9.
1/9
2/9
3/9
4/9
5/9
6/9
7/9 <<<
8/9
9/9

Of these multiples of 1/9, 7/9 is in the interval I.
 
  • #3
Thank you! i get it now..

would this also mean that there are an infinite number of IRRATIONALS on every interval "I" as well? ifso, how would i go about stating that theorem?
 
  • #4
That's true too. I think you could use the same idea: find an irrational number r that is smaller than the length of the interval, then multiply it by an integer n that is large enough so that a < nr < b.
 

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