- #1
Nikitin
- 735
- 27
Hey! In an example in my textbook, the complex equation z2 +2i*z-(1+i) = 0
is solved using the quadratic formula, so that it ends up with:
z= -i ± √i = -i ± (1+i)/√2 = ...etc.
Uhm.. I got 2 questions:
1) Why isn't the first solution (-i ± √i) acceptable?
2) How does √i = (1+i)/√2 ? Only thing I know is that the root of two is the length of 1+i, but how does dividing 1+i with its length give √i?
thanks
is solved using the quadratic formula, so that it ends up with:
z= -i ± √i = -i ± (1+i)/√2 = ...etc.
Uhm.. I got 2 questions:
1) Why isn't the first solution (-i ± √i) acceptable?
2) How does √i = (1+i)/√2 ? Only thing I know is that the root of two is the length of 1+i, but how does dividing 1+i with its length give √i?
thanks
Last edited: