- #1
RadiationX
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- 0
Rules of Summation...Help Me Please
I have a vauge idea of what these rules mean:
1. [tex]\sum^n_{i=1}c=cn[/tex]
2. [tex]\sum^n_{i=1}i=\frac{n(n+1)}_{2}[/tex]
3. [tex]\sum^n_{i=1}i^2=\frac{n(n+1)(2n+1)}_{6}[/tex]
4. [tex]\sum^n_{i=1}i^3=\frac{n^2(n+1)^2}_4[/tex]
are these rules saying that if i have an expression, (i) raised to a power from 1 to 3 then i use the above rules? How would you solve the following problem?
[tex]\sum^n_{i=1}\frac{(i + 1)}_{n^2}[/tex] for n = 10,100,1000,10000
i know that the answer reduces to [tex]\frac{(n + 3)}_{2n}[/tex]
and you make some substitutions, but how is this done? any help would be appreciated. It's three am and I'm still trying to figure this out!
I have a vauge idea of what these rules mean:
1. [tex]\sum^n_{i=1}c=cn[/tex]
2. [tex]\sum^n_{i=1}i=\frac{n(n+1)}_{2}[/tex]
3. [tex]\sum^n_{i=1}i^2=\frac{n(n+1)(2n+1)}_{6}[/tex]
4. [tex]\sum^n_{i=1}i^3=\frac{n^2(n+1)^2}_4[/tex]
are these rules saying that if i have an expression, (i) raised to a power from 1 to 3 then i use the above rules? How would you solve the following problem?
[tex]\sum^n_{i=1}\frac{(i + 1)}_{n^2}[/tex] for n = 10,100,1000,10000
i know that the answer reduces to [tex]\frac{(n + 3)}_{2n}[/tex]
and you make some substitutions, but how is this done? any help would be appreciated. It's three am and I'm still trying to figure this out!