- #1
makhoma
- 10
- 0
vector identity??
The text that I'm reading has a line that reads
[tex]\left(\mathbf{b}\mathbf{k}\cdot-\mathbf{b}\cdot\mathbf{k}\right)\mathbf{v}=\omega\mathbf{B}[/tex]
and I'm not sure what it means by [itex]\mathbf{b}\mathbf{k}[/itex]; it's clearly not the dot product nor the cross product. A line or two below it gives a matrix of the equation:
[tex]\left(\begin{array}{ccc}-k_{||}b & 0 & 0 \\ 0 & -k_{||}b &0 \\ k_\perp b & 0 & 0 \end{array}\right)\left(\begin{array}{c} v_x \\ v_y \\ v_z\end{array}\right)=\omega\left(\begin{array}{c}B_x \\ B_y \\ B_z\end{array}\right)[/tex]
for [itex]\mathbf{b}=(0,0,b)[/itex] and [itex]\mathbf{k}=(k_\perp,0,k_{||})[/itex] which looks like maybe [itex]\mathbf{b}\mathbf{k}\cdot\mathbf{v}=0[/itex] for x and y directions but not for z??Any suggestions?
unknown
see above
Homework Statement
The text that I'm reading has a line that reads
[tex]\left(\mathbf{b}\mathbf{k}\cdot-\mathbf{b}\cdot\mathbf{k}\right)\mathbf{v}=\omega\mathbf{B}[/tex]
and I'm not sure what it means by [itex]\mathbf{b}\mathbf{k}[/itex]; it's clearly not the dot product nor the cross product. A line or two below it gives a matrix of the equation:
[tex]\left(\begin{array}{ccc}-k_{||}b & 0 & 0 \\ 0 & -k_{||}b &0 \\ k_\perp b & 0 & 0 \end{array}\right)\left(\begin{array}{c} v_x \\ v_y \\ v_z\end{array}\right)=\omega\left(\begin{array}{c}B_x \\ B_y \\ B_z\end{array}\right)[/tex]
for [itex]\mathbf{b}=(0,0,b)[/itex] and [itex]\mathbf{k}=(k_\perp,0,k_{||})[/itex] which looks like maybe [itex]\mathbf{b}\mathbf{k}\cdot\mathbf{v}=0[/itex] for x and y directions but not for z??Any suggestions?
Homework Equations
unknown
The Attempt at a Solution
see above
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