Understanding the Vector Potential for a Given Function

In summary, In Stweart, "Calculus" & Marsden & Tromba "Vector Calculus", or your favorite text, vectors are represented by their components, while in this conversation they are represented by the vector field and potential function.
  • #1
Treadstone 71
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[tex]\mathbf{F}(x,y,z)=(x^2+yz,y^2+zx,-2z(x+y))[/tex] Find the vector potential.

A vector potential [tex]\mathbf{V}[/tex] would have to satisfy

[tex]\mathbf{V}_x=x^2+yz[/tex]
[tex]\mathbf{V}_y=y^2+zx[/tex]
[tex]\mathbf{V}_z=-2z(x+y)[/tex]

So,

[tex]\mathbf{V}=\frac{x^3}{3}+xyz+M(y)+N(z)[/tex]
[tex]\Rightarrow \mathbf{V}_y=zx+M_y(y)[/tex]
[tex]\Rightarrow M_y(y)=y^2[/tex]
[tex]\Rightarrow \mathbf{V}=\frac{x^3}{3}+xyz+\frac{y^3}{3}+N(z)[/tex]
[tex]\Rightarrow \mathbf{V}_z=xy+N_z(z)[/tex]

However, here I can't find [tex]N_z(z)[/tex].
 
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  • #2
??

F is a vector field, right?,,, if so, a SCALAR Potential function V satisfies the relations you have written: F=(-) grad V, ( the minus sign is just a convention used in certain physical problems and may be removed).

A vectorial potential function A of F, (as it is understood in physics) must satisfy F= rot A, where rot is the rotational operator.

In general, You may try to express F as

F= (-)grad V + rot A

If you really mean a Vector Potential then it must be the rot part, i think.
 
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  • #3
nomenclature

I think is the opposite, V is the potential function, and scalar function V=V(x,y,z) and F is the Vector Field F=f1(x,y,z) i + f2(x,y,z) j + f3(x,y,z) k , where i,j,k are unit orthogonal vectors in the x,y,z directions.


If V were a vector (potential) function, you won't be able to apply to it the del operator as impliying 'gradient'.
 
  • #4
I don't think so

Nop, F is a vector function!


del=nabla= grad operator is a vector operator

del= (d/dx) i + (d/dy) j + (d/dz) k

hence V, NEEDS to be and scalar function in order to apply to it the del operator and hence the nomenclature scalar potential for V.

When you apply del to V, you get a VECTOR function

F= del V= dV/dx i + dV/dy j + dV/dz k= [dV/dx, dV/dy, dV/dz], and hence the nomenclature vector field for F.


If V is a vector function (potential) the application of the operator del to it makes any sense, at least in the 'traditional' sense. (if you think in diads or something like that then maybe).

a Vector potential field for a vector field F may be obtained, for instance, by the cross product of del operater and another vector field V1

so that

F= del x V1


And example from physics.

The Electric Field may be expresed as

E= - del (phi) with phi being the SCALAR electric potencial

and the Magnetic Field as

B= del x A with A being the VECTOR magnetic potential
 
  • #5
http://en.wikipedia.org/wiki/Potential, I am a math guy but I have taken a fair bit of physics. Arguments such as these seem to occur frequently between the two opposing camps. I go by what I read in my books. I am aware that there is an underlying physical interpretation which you seem to be commenting on. I have been referencing a couple of standard Calculus books, but I found a link at wikipedia which references my claim. The book which has the defintion I read, and more or less regurgated in my last post, is Larson, Hostetler Edwards, Mulitivariable Calculus 6th edition page 988.
 
  • #7
Notice that in the links you post they refer to F as a vector field and V as the scalar potential. That Is what I'm saying.

I know that there may be ambiguities in nomenclature between different sciences, but notice also that in the original post he/she says: 'find the vector potential', so, either he/she made a mistake and was trying to say scalar potential or he/she REALLY meaned vector potential, that is what motivated my post.
 
  • #8
I mean the potential of a conservative vector field. The choice of V is completely arbitrary. Sorry about the confusion, I am in math and didn't realize notations could be ambiguous to the physics people. I've since then solved it. Thanks for the help.
 
  • #9
nop

Ok, lats post about this, because he/she has already solved the problem.

If F=del(V) , F is the conservative vector field and V the scalar potential.

If V=del(F), V is the conservative vector field and F the scalar potential.

What I've posted is ok for both cases. No confusion.

F in the original post has components, it's a vector field, and hence
F=del(V) is the one that applies.

http://ltcconline.net/greenl/courses/20/vectorIntegration/vectorFields.htm

http://mathworld.wolfram.com/ConservativeField.html

See also, Stweart, "Calculus" & Marsden & Tromba "Vector Calculus", or your favorite text ;).
 
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  • #10
Now I am confused. To many references to F and V. What I wrote above is wrong. F and V should be transposed. I was referencing to the F and V in my book. The problem is just really familiar to the ones I encountered while being a reader for multi calc so the solution was more or less profunctory. Unfortunately my inability to correctly delineate my solution probably did more harm than good. Sorry.
 

Related to Understanding the Vector Potential for a Given Function

1. What is a vector potential?

A vector potential is a mathematical concept used in electromagnetism to describe the magnetic field in terms of a vector quantity. It is closely related to the magnetic vector potential and is used to help calculate the magnetic field in a given region.

2. Why is finding the vector potential important?

Finding the vector potential is important because it allows us to better understand and predict the behavior of electromagnetic fields. It is also a crucial step in solving many practical problems in fields such as engineering and physics.

3. How do you find the vector potential?

The vector potential can be found by solving the vector potential equation, which is a partial differential equation that describes the relationship between the magnetic field and the vector potential. This equation can be solved using various mathematical techniques, such as using the Helmholtz decomposition or the Coulomb gauge.

4. What are some applications of the vector potential?

The vector potential has many applications in various fields such as engineering, physics, and geophysics. It is used in the study of electromagnetic fields, in the design of electrical circuits and devices, and in the modeling of fluid flow and heat transfer. It is also used in geophysics to understand the behavior of Earth's magnetic field.

5. Are there any limitations to using the vector potential?

While the vector potential is a useful tool in understanding electromagnetic fields, it does have some limitations. It cannot be directly measured in experiments and must be calculated using mathematical techniques. Additionally, in certain situations, such as in the presence of time-varying electric fields, the vector potential may not accurately describe the magnetic field and other equations may need to be used.

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