Uniform Circular Motion; Need help with deriving equations.

In summary, the conversation is about a physics lab on uniform circular motion, where the variables of mass, radius, and force tension are measured and manipulated. The relationship between these variables and the frequency of revolution is being tested through graphical analysis. The equation Fc = 4π²mrf² is used to calculate the magnitude of the net force causing the acceleration in uniform circular motion, and students are asked to rearrange the equation to isolate frequency and compare it with the equation they derived. However, there may be discrepancies due to the use of time period instead of frequency in the graphs.
  • #1
n3w ton
19
0

Homework Statement


Hi I'm doing a physics lab about uniform circular motion to measure frequency and to compare it to mass,radius and force tension.

(A & B) I did
(C,D, E) I need help

(a) What variables are being measured / manipulated in this lab? What type of relationship is being tested? (radius, mass, force tension/force causing centripetal force)

(b) Graph the relationship between the frequency of revolution and each of the following:
• the magnitude of the tension force [force causing the circular motion(centripetal force)]
• the radius of the circular path
• the mass of the object

**■→(c) Find the proportionalities between frequency of revolution and the variables in radius, mass, and force of tension/centripetal force.

**■→(d) Derive an equation for the frequency in terms of the tension, the radius, and the mass by combining your results from (c) and using your results from (b) to verify.

**■→(e) The following relationship gives the magnitude of the net force causing the acceleration of an object in uniform circular motion:
Fc = 4π²mrf²
Rearrange this equation to isolate the frequency. Compare this result with the equation you derived in (d). Indicate the likely causes for any discrepancies.

Data: http://i.imgur.com/dLpyP.png

Frequency vs Force Graph: http://i.imgur.com/fyFci.png

Frequency vs Mass Graph: http://i.imgur.com/GJ2ms.png

Frequency vs Radius Graph: http://i.imgur.com/JtxbR.png

Homework Equations


Fc = 4π²mrf²


The Attempt at a Solution


C) and D) I am stuck at

E)
Fc = 4π²mrf²
[itex]\sqrt{}\frac{Fc}{4π²mr}[/itex]
 
Physics news on Phys.org
  • #2
n3w ton said:

Homework Statement


Hi I'm doing a physics lab about uniform circular motion to measure frequency and to compare it to mass,radius and force tension.

(A & B) I did
(C,D, E) I need help

(a) What variables are being measured / manipulated in this lab? What type of relationship is being tested? (radius, mass, force tension/force causing centripetal force)

(b) Graph the relationship between the frequency of revolution and each of the following:
• the magnitude of the tension force [force causing the circular motion(centripetal force)]
• the radius of the circular path
• the mass of the object

**■→(c) Find the proportionalities between frequency of revolution and the variables in radius, mass, and force of tension/centripetal force.

**■→(d) Derive an equation for the frequency in terms of the tension, the radius, and the mass by combining your results from (c) and using your results from (b) to verify.

**■→(e) The following relationship gives the magnitude of the net force causing the acceleration of an object in uniform circular motion:
Fc = 4π²mrf²
Rearrange this equation to isolate the frequency. Compare this result with the equation you derived in (d). Indicate the likely causes for any discrepancies.

Data: http://i.imgur.com/dLpyP.png

Frequency vs Force Graph: http://i.imgur.com/fyFci.png

Frequency vs Mass Graph: http://i.imgur.com/GJ2ms.png

Frequency vs Radius Graph: http://i.imgur.com/JtxbR.png

Homework Equations


Fc = 4π²mrf²


The Attempt at a Solution


C) and D) I am stuck at

E)
Fc = 4π²mrf²
[itex]\sqrt{}\frac{Fc}{4π²mr}[/itex]

Your graphs are not extensive enough - they must include the origin (0,0) - not necessarily as a point, but with the axes long enough for them to show up.

With graphical analysis, the only line you can confidently interpret is a straight line passing through the origin.

if y vs x is not straight, you can try y vs 1/x or y vs x2 or or y vs 1/x2 or y vs x2 of y vs √x or y vs 1/√x to see if any of them are a straight line through the origin [or close - there may be uncertainties in your measurements]

suppose y vs 1/√x was such a straight line.

That means y is proportional to 1/√x or y = k/√x or y2x = k
 
  • #3
uhmm.. time for one cycle is 1/frequency.
 
  • #4
MrWarlock616 said:
uhmm.. time for one cycle is 1/frequency.

Looking at your results, I am not sure the figure you call frequency is in fact frequency.
It looks more like the Period to me - ie the time for one cycle.
You possibly need to follow the step you mention above.
 
  • #5
PeterO said:
Looking at your results, I am not sure the figure you call frequency is in fact frequency.
It looks more like the Period to me - ie the time for one cycle.
You possibly need to follow the step you mention above.
Yes exactly, that's what I said. The graphs are obviously wrong because he has used time period instead of frequency.
peter, I didn't ask this question..n3w ton did. :P
 

Related to Uniform Circular Motion; Need help with deriving equations.

1. What is uniform circular motion?

Uniform circular motion is the motion of an object moving along a circular path at a constant speed. This means that the object is moving with a constant velocity tangent to the circle at all points.

2. How is uniform circular motion different from other types of motion?

Uniform circular motion is different from other types of motion because it involves a constant change in direction, but the speed remains the same. This is in contrast to linear motion, where the direction and speed can both change.

3. What is the equation for centripetal acceleration in uniform circular motion?

The equation for centripetal acceleration in uniform circular motion is a = v^2/r, where a is the centripetal acceleration, v is the velocity of the object, and r is the radius of the circular path.

4. How do you derive the equation for centripetal acceleration?

To derive the equation for centripetal acceleration, we can use the equation for acceleration, a = Δv/Δt, and substitute in the definition of velocity in circular motion, v = 2πr/T, where T is the time it takes for one full rotation. By rearranging the equation, we get a = (2πr/T)^2 * r, which simplifies to a = v^2/r.

5. How is uniform circular motion related to Newton's laws of motion?

Uniform circular motion is related to Newton's laws of motion because it follows the second law of motion, F = ma. In circular motion, the force, known as the centripetal force, is responsible for changing the direction of the object's velocity and keeping it moving in a circular path. This force is equal to the mass of the object times its centripetal acceleration, F = ma = mv^2/r.

Similar threads

  • Introductory Physics Homework Help
2
Replies
55
Views
1K
  • Introductory Physics Homework Help
Replies
7
Views
2K
  • Introductory Physics Homework Help
Replies
17
Views
7K
  • Introductory Physics Homework Help
Replies
2
Views
758
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
12
Views
2K
  • Introductory Physics Homework Help
Replies
10
Views
2K
  • Introductory Physics Homework Help
Replies
8
Views
2K
  • Introductory Physics Homework Help
Replies
6
Views
2K
  • Introductory Physics Homework Help
Replies
7
Views
3K
Back
Top