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winnayy
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Homework Statement
A proposed space station consists of a circular tube that will rotate about its center (like a tubular bicycle tire), as shown in the figure (http://session.masteringphysics.com/problemAsset/1057181/4/GIANCOLI.ch05.p048.jpg). The circle formed by the tube has a radius of about 1.9 km. What must be the rotation speed (revolutions per day) if an effect equal to gravity at the surface of the Earth (1.0g) is to be felt?
g = 9.8 m/s2
r = 1900m/2 = 950m
Homework Equations
g = (4[tex]\pi[/tex]r2/T2)
The Attempt at a Solution
Solve for T:
T = [tex]\sqrt{}[/tex](4[tex]\pi[/tex]r2/g)
T = 2[tex]\pi[/tex][tex]\sqrt{}[/tex](r/g)
Plug in known values:
T = 2[tex]\pi[/tex][tex]\sqrt{}[/tex](950m/9.8m/s2) = 61.86266614 sec/rev
Seconds in a day:
(24hr/day)(60min/hr)(60sec/min) = 86400sec
(86400s/day)/(61.86266614sec/rev) = 1396.642936 rev/day
Rounded to two significant figures, this is 1400 rev/day, but MasteringPhysics keeps telling me I'm wrong. I've tried another way finding the velocity and diving that into the circumference to get T, and I get the same answer... so I'm confused as to where my mistake lies.
Thanks in advance for the help!
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