Uniformly Charged Ring Acting on a Particle

In summary, we are trying to solve for the electric force on a particle located at a distance z above a uniform ring of charge Q, and also determine its potential energy when the charge is at the center of the ring. Using the equation F=kqQz/(z^2+a^2)^3/2, we can calculate the electric force. To find the potential energy, we can use the formula W=integral of[F(dot)dl], where dl represents the path from one point to another. In this case, we can choose the path along the z axis to calculate the potential energy.
  • #1
acedeno
36
4

Homework Statement


Solve for the Electric force exerted on a Particle a distance z above a uniform ring of charge Q.

Determine the potential energy of the charge where the charge lies directly in the center.

Homework Equations


F=kq1q1/r^2


The Attempt at a Solution


Knowing E=F/q I just solved for E then multiplied it by the charge q.

resulting in E=kQz/(z^2+a^2)^3/2 thus, F=kqQz/(z^2+a^2)^3/2

Now, I'm not sure about how to go about expressing the potential energy.
My intuition tells me to do Work=Potential Energy, so,
W= integral of[F(dot)dl]

I'm not sure where to go from here because I'm not sure as to what I should make dl.
 
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  • #2
Potential energy is defined for conservative forces, so as the force is negative gradient of the potential energy. The work of a conservative force when a body moves from point A to B is independent on the path.
You can calculate the potential energy difference by integrating the force along any path form A to B:

[itex] U(B)-U(A) =-\int_{A}^{B}(\vec {F} \cdot \vec{dl} ) [/itex]

The zero point of the potential energy is arbitrary. In Electrostatics, it is at infinity in most cases. For the path, you can chose the most convenient one. For your problem, it can be along the z axis.

ehild
 

FAQ: Uniformly Charged Ring Acting on a Particle

How does a uniformly charged ring affect a particle?

A uniformly charged ring exerts a force on a particle placed at any point in its vicinity. The direction of the force is towards the center of the ring and its magnitude is dependent on the charge of the ring, the charge of the particle, and the distance between them.

What is the formula for the force exerted by a uniformly charged ring on a particle?

The formula for the force exerted by a uniformly charged ring on a particle is F = (kQq)/(r²), where F is the force in Newtons, k is the Coulomb constant, Q is the charge of the ring in Coulombs, q is the charge of the particle in Coulombs, and r is the distance between the ring and the particle in meters.

How does the force from a uniformly charged ring change as the distance from the ring increases?

The force from a uniformly charged ring decreases as the distance from the ring increases. This is because the force is inversely proportional to the square of the distance between the ring and the particle, as shown in the formula F = (kQq)/(r²).

Can the force from a uniformly charged ring be repulsive?

Yes, the force from a uniformly charged ring can be repulsive if the charges of the ring and the particle are of the same sign. In this case, the force would push the particle away from the center of the ring.

Is there an electric field created by a uniformly charged ring?

Yes, a uniformly charged ring creates an electric field in its surrounding space. This electric field is directed away from the ring if the charge is positive, and towards the ring if the charge is negative. The strength of the electric field is dependent on the charge of the ring and the distance from the ring.

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