Unique Elements of Relatively Prime Order

In summary, we have shown that for a group G and an element g in G such that |g| = mn, where gcd(m, n) = 1, there exist unique elements a and b in G such that g = ab = ba and |a| = m and |b| = n. This is proven by choosing a = gnt and b = gms, and using the fact that gcd(m, n) = 1 and ms + nt = 1. To prove uniqueness, we assume that there exist other elements a' and b' with the same properties, and use the fact that <a> = <a'> and <b> = <b'>, which leads to a = a'
  • #1
e(ho0n3
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Homework Statement
Let G be a group and let g be an element G such that |g| = mn, where gcd(m, n) = 1. Show that there are unique elements a, b in G such that g = ab = ba and |a| = m and |b| = n.

The attempt at a solution
Since gcd(m, n) = 1, there are integers s and t such that ms + nt = 1. Hence g = gms+nt = gmsgnt. Let a = gnt and b = gms. Then g = ab = ba. We also have that |a| ≤ m and |b| ≤ n.

I'm having trouble showing that |a| = m and |b| = n. Also, the fact that s and t are not unique proves that a and b are not unique right? This is as my thought process has taken me. Any tips?
 
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  • #2
e(ho0n3 said:
Since gcd(m, n) = 1, there are integers s and t such that ms + nt = 1.

I'm having trouble showing that |a| = m and |b| = n. Also, the fact that s and t are not unique proves that a and b are not unique right?

Hi e(ho0n3! :smile:

s and t are unique (to prove it, assume they're not).

And |a| must be a factor of mn, so … ? :smile:
 
  • #3
tiny-tim said:
s and t are unique (to prove it, assume they're not).
I don't think so: Take m = 7 and n = 11. Then gcd(7, 11) = 1 and 7(-3) + 11(2) = 7(8) + 11(-5) = 1.

And |a| must be a factor of mn, so … ? :smile:
Why must it be a factor of mn?
 
  • #4
Notice that |g^m| = |g|/gcd(|g|, m) = n. So |g^(ms)|=<fill blank>. Similarly, |g^(nt)|=<fill blank>.

So now you've found the appropriate a and b. To show uniqueness, suppose that g=a'b'=b'a' and |a'|=m and |b'|=n, then show that a'=a and b'=b. The fact that |a'|=|a|=m and |b'|=|b|=n is important here.
 
  • #5
We have that |b| = mn / gcd(mn, ms) = n / gcd(n, s) and |a| = mn / gcd(mn, nt) = m / gcd(m, t). Are you suggesting that gcd(n, s) = gcd(m, t) = 1 because ms + nt = 1?

Concerning uniqueness, I've managed to get bm = (b')m from (ab)m = (a'b')m and similarly an =(a')n. How do I continue.
 
  • #6
Are you suggesting that gcd(n, s) = gcd(m, t) = 1 because ms + nt = 1?
If gcd(n,s)>1, what could you say about ms + nt?

How do I continue.
Use your existing information.
 
  • #7
CoCoA said:
If gcd(n,s)>1, what could you say about ms + nt?
I could say that gcd(n,s) divides ms + nt since it divides ms and nt, but this means it would divide 1, which is impossible. I get it know.

Use your existing information.
Somehow I need to get rid of the n in an = (a')n. I'm thinking of the following: Consider the cyclic group <a>. Since <a> has order m and n is relatively prime to m, we must have <an> = <a>. We also get that <(a')n> = <a'>, hence <a> = <a'> and a = a'?
 
  • #8
You already used the trick required here: b = bnt bms.
 
  • #9
Ah, right! That hadn't occurred to me. Thanks a lot.
 

FAQ: Unique Elements of Relatively Prime Order

What are "Unique Elements of Relatively Prime Order"?

"Unique Elements of Relatively Prime Order" refers to a set of numbers that have no common factors other than 1. This means that when two numbers in the set are multiplied together, their product will not have any factors in common with the other numbers in the set.

How do you determine if two numbers are relatively prime?

To determine if two numbers are relatively prime, you can use the Euclidean algorithm. This involves finding the greatest common divisor (GCD) of the two numbers. If the GCD is 1, then the numbers are relatively prime.

What are some examples of "Unique Elements of Relatively Prime Order"?

Examples of "Unique Elements of Relatively Prime Order" include 3 and 5, 7 and 11, and 13 and 17. These pairs of numbers have no common factors other than 1, making them relatively prime.

Why are "Unique Elements of Relatively Prime Order" important?

"Unique Elements of Relatively Prime Order" are important in number theory and cryptography. They are used in encryption algorithms to ensure that the message cannot be easily decoded by finding common factors among the numbers.

Is it possible for a set of numbers to have more than two "Unique Elements of Relatively Prime Order"?

Yes, it is possible for a set of numbers to have more than two "Unique Elements of Relatively Prime Order". For example, the set {2, 3, 5, 7} has four "Unique Elements of Relatively Prime Order" because each number is only divisible by 1 and itself, and none of the other numbers in the set.

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