- #1
Grand
- 76
- 0
Homework Statement
Theorem
If, for given [tex]A[/tex], both operators [tex]A_l^{-1}[/tex] and [tex]A_r^{-1}[/tex] exist, they are unique and
[tex]A_l^{-1}=A_r^{-1}[/tex]
The proof is rather straightforward, at least the first part of it:
[tex]A_l^{-1}A=I/\leftarrow A_r^{-1}[/tex]
[tex]A_l^{-1}AA_r^{-1}=A_r^{-1} (1)[/tex]
[tex]A_l^{-1}A=I/\rightarrow A_l^{-1}[/tex]
[tex]A_l^{-1}AA_r^{-1}=A_l^{-1} (2)[/tex]
Therefore
[tex]A_l^{-1}=A_r^{-1}[/tex]
However, then they say that this proof holds for any pair of operators [tex]A_l^{-1}[/tex] and [tex]A_r^{-1}[/tex] (which I can't deny) and that eqs (1) and (2) ensure there exists only one such pair, which I can't understand. I would be very grateful if someone explains to me why is that.