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MD_Programmer
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Homework Statement
The power available (output) is measured by the velocity at which you are moving and the thrust
required to create that movement. NOTE: Conversions for proper units are provided below
equation.
Power Available: Pout = Tc * v
where: Pout = power available (watts)
Tc = Calibrated thrust (grams)
v = wind tunnel velocity (m/s)
In order to determine the efficiency, the units must cancel. To convert the units so that the output
power is in watts, use the following information:
can't get the power right help?
Homework Equations
1 gram = 0.002205 lbs.
1 m/s = 3.28 ft/s
1 horsepower = 550 lb*ft/sec
1 horsepower = 745.7 watts
v = 3 m/s
Tc = 0.0040 g
The Attempt at a Solution
(0.0040*0.002205) = 8.82 E-6
(3*3.28) = 9.84 ft/s
((8.82 E-6 * 9.84) *550) / 745.7 = 6.401212284 E-5 watts
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