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Q: a 4.6 kg rocket is launched directly upward from Earth at 9 km/s .
What altitude above Earth's surface does the rocket reach?
Relevant equations: v=[itex]\sqrt{2Gm/r}[/itex]
Eg=Gm1m2(1/r1-1/r2)
my attempt: i figured i should use the first equation which contains velocity so i did:
9000=[itex]\sqrt{2(6.67x10^-11)(5.99x10^24/r}[/itex]
9000^2=2(6.67x10^-11)(5.99x10^24)/r
r=9,865 km
the answer is 1.21x10^4 km
please help, thanks!
What altitude above Earth's surface does the rocket reach?
Relevant equations: v=[itex]\sqrt{2Gm/r}[/itex]
Eg=Gm1m2(1/r1-1/r2)
my attempt: i figured i should use the first equation which contains velocity so i did:
9000=[itex]\sqrt{2(6.67x10^-11)(5.99x10^24/r}[/itex]
9000^2=2(6.67x10^-11)(5.99x10^24)/r
r=9,865 km
the answer is 1.21x10^4 km
please help, thanks!