- #1
shamieh
- 539
- 0
Use algebraic manipulation to prove that x+yz=(x+y)(x+z) Note that this is
the distributive rule,
So I have:
(x + y)(x + z) = xx + xz + xy + zy
= x + xz + xy + zy
= x(1 + z + y) zy
=x * 1 + (z + y)(zy)
= x + ((zzy + yzz)
= x +y + z?
but i need x + yz... But I don't understand what is going on in the right side
the distributive rule,
So I have:
(x + y)(x + z) = xx + xz + xy + zy
= x + xz + xy + zy
= x(1 + z + y) zy
=x * 1 + (z + y)(zy)
= x + ((zzy + yzz)
= x +y + z?
but i need x + yz... But I don't understand what is going on in the right side