- #1
GravityX
- 19
- 1
- Homework Statement
- I have to show the following with the virial theorem ##E=\langle \cal H \rangle_k## ##=k_bT \sum\limits_{i=1}^{N}a_i##
- Relevant Equations
- none
The expression ##\langle \cal H \rangle_k## is the expected value of the canonical ensemble.
The Hamiltonian is defined as follows, with the scaling ##\lambda##
##\lambda \cal H ## : ##\lambda H(x_1, ...,x_N)=H(\lambda^{a_1}x_1,....,\lambda^{a_N}x_N)##
As a hint, I should differentiate the Hamiltonian with respect to ##\lambda##
Unfortunately, I don't know how exactly I should do this, i.e. form the derivative, I have now proceeded in such a way that I have formed the differential
$$H(\lambda^{a_1}x_1,...\lambda^{a_N}x_N)=\lambda^{a_1}x_1\frac{\partial H}{\partial x_1}+...\lambda^{a_N}x_N\frac{\partial H}{\partial x_N}$$
Then the derivative should look like this,
$$\frac{\partial}{\partial \lambda}H(\lambda^{a_1}x_1,...\lambda^{a_N}x_N)=a_1\lambda^{a_1-1}x_1\frac{\partial H}{\partial x_1}+...a_N\lambda^{a_N-1}x_N\frac{\partial H}{\partial x_N}$$
Is this correct
The Hamiltonian is defined as follows, with the scaling ##\lambda##
##\lambda \cal H ## : ##\lambda H(x_1, ...,x_N)=H(\lambda^{a_1}x_1,....,\lambda^{a_N}x_N)##
As a hint, I should differentiate the Hamiltonian with respect to ##\lambda##
Unfortunately, I don't know how exactly I should do this, i.e. form the derivative, I have now proceeded in such a way that I have formed the differential
$$H(\lambda^{a_1}x_1,...\lambda^{a_N}x_N)=\lambda^{a_1}x_1\frac{\partial H}{\partial x_1}+...\lambda^{a_N}x_N\frac{\partial H}{\partial x_N}$$
Then the derivative should look like this,
$$\frac{\partial}{\partial \lambda}H(\lambda^{a_1}x_1,...\lambda^{a_N}x_N)=a_1\lambda^{a_1-1}x_1\frac{\partial H}{\partial x_1}+...a_N\lambda^{a_N-1}x_N\frac{\partial H}{\partial x_N}$$
Is this correct