- #1
jaydnul
- 558
- 15
I have a power brick (transformer) that sends 12V, 17.9A to a device. I have another device that requires 12V, 10.83A. If I put a 1.7 ohm resistor in parallel to draw some of the current:
[itex]\frac{12V}{17.90A-10.83A}=1.697312[/itex]
Could I use it to power the 10.83A device? I'm just not sure if it is as simple as that.
Also, when it says 17.9A on the transformer, does that just mean that is the MAX current that can be drawn, or is that what it is always sending?
Edit: Sorry I should add that it is an external power supply, so it is outputting DC not AC.
Thanks
[itex]\frac{12V}{17.90A-10.83A}=1.697312[/itex]
Could I use it to power the 10.83A device? I'm just not sure if it is as simple as that.
Also, when it says 17.9A on the transformer, does that just mean that is the MAX current that can be drawn, or is that what it is always sending?
Edit: Sorry I should add that it is an external power supply, so it is outputting DC not AC.
Thanks
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