- #1
Stalker_VT
- 10
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how do you use the change of variable:
[itex]\xi[/itex] = x - ct
on the PDE
ut + c ux = 0
where u(t,x) = v(t,x-ct) = v(t,[itex]\xi[/itex])
to get
vt = 0
I am trying to follow the steps of Peter J. Olver in this document http://www.math.umn.edu/~olver/pd_/lnw.pdf starting on pg 4 but get stuck here...i think i am missing an important calculus concept but cannot figure out what. He says to use the chain rule but i cannot figure out how that helps.
Any help GREATLY appreciated
[itex]\xi[/itex] = x - ct
on the PDE
ut + c ux = 0
where u(t,x) = v(t,x-ct) = v(t,[itex]\xi[/itex])
to get
vt = 0
I am trying to follow the steps of Peter J. Olver in this document http://www.math.umn.edu/~olver/pd_/lnw.pdf starting on pg 4 but get stuck here...i think i am missing an important calculus concept but cannot figure out what. He says to use the chain rule but i cannot figure out how that helps.
Any help GREATLY appreciated
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