Using double angles to find value of

In summary, you would use the double angle formulas for sin(2x) and cos(2x). sin(3x) = sin(2x + x) = sin(2x)cos(x) + cos(2x)sin(x). Then you use the double-angle formulas for sin(2x) and cos(2x).
  • #1
aeromat
114
0

Homework Statement


sin2x.png

Homework Equations


doubleangleformulae.png

The Attempt at a Solution


I know the following:
sin^2x = 8/9
the hyp. is 9, the "y" value is 8.
Therefore, the "x" value has to be [tex]\sqrt{17}[/tex]

What is the next step?
 
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  • #2
You are given that x is in Quadrant II, so sin(x) >= 0 and cos(x) <= 0.
You are also given that sin2(x) = 8/9, so you can easily find cos2(x).

Now find sin(x) and cos(x) by taking the square root with the appropriate sign, and you can evaluate sin(2x) = 2sin(x)cos(x).
 
  • #3
Im sorry I should've really thought before I posted. I actually got through A,B, and C. However, d (with sin3(x)) is confusing me.

The double angle formula for it will be:
sin3x = sin0.5xcos0.5x correct?
But then, when I sub in known values, I don't receive the correct answer:

-10*root 2
--------------
27
 
  • #4
aeromat said:
Im sorry I should've really thought before I posted. I actually got through A,B, and C. However, d (with sin3(x)) is confusing me.

The double angle formula for it will be:
sin3x = sin0.5xcos0.5x correct?
No - why would you think that. sin(3x) = sin(2x + x). Use the addition formula and then the double angle formula to get things in terms of sin(x) and cos(x), which you already know.
aeromat said:
But then, when I sub in known values, I don't receive the correct answer:

-10*root 2
--------------
27
 
  • #5
I'm sorry but we just started this unit and I am not sure how I would do that:
Use the addition formula and then the double angle formula to get things in terms of sin(x) and cos(x), which you already know.
 
  • #6
sin(3x) = sin(2x + x) = sin(2x)cos(x) + cos(2x)sin(x)

Then you use the double-angle formulas for sin(2x) and cos(2x).
 
  • #7
Bohrok said:
sin(3x) = sin(2x + x) = sin(2x)cos(x) + cos(2x)sin(x)

Then you use the double-angle formulas for sin(2x) and cos(2x).

I'm sorry but I have no idea how you would do that. Would you mind explaining to me step-by-step? :confused:
 
  • #8
Well you have sin(2x)cos(x) + cos(2x)sin(x). In other words. Use the double angle formulas for the bold areas. Like the first part would be 2sin(x)cos(x)cos(x) or 2sin(x)cos²(x). The second part is to substitute one of the double angle formulas for cos(2x), look at the second version as I think that one will help a lot, and then substitute your x values for each. Hope I make sense! :D
 

FAQ: Using double angles to find value of

How do you use double angles to find the value of a trigonometric function?

To use double angles, you first need to know the double angle identities for the specific trigonometric function you are working with. Then, you can substitute the double angle value into the identity and simplify to find the value of the function.

Can double angles be used for all trigonometric functions?

Yes, there are double angle identities for all six trigonometric functions (sine, cosine, tangent, cotangent, secant, and cosecant). However, some identities may be more complex than others.

3. Are there any special cases when using double angles to find values?

Yes, there are a few special cases where the double angle identities do not apply. For example, when the angle is equal to 0 or π/2, the double angle values will be the same as the original angle value.

4. What are some benefits of using double angles to find values?

Using double angles can be helpful when simplifying complex trigonometric expressions or solving trigonometric equations. They can also provide a more precise value compared to using a calculator.

5. How can double angles be applied in real-world scenarios?

Double angles can be used in various fields such as engineering, physics, and astronomy to calculate distances, angles, and other measurements. They can also be used in navigation and surveying.

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