Using Gauss' Law to Calculate electric field near rod.

In summary, the conversation discusses the application of Gauss's Law for electric flux in calculating the field at a point near a uniformly charged rod. It is mentioned that symmetry arguments typically allow for the calculation of the radial component of the electric field, but in the case of a finite rod, these arguments may not hold. The concept of evaluating the dot product in this scenario is also discussed.
  • #1
Nathan B

Homework Statement


No variables, just a conceptual question.

Homework Equations


Flux = EA = Q/ε

The Attempt at a Solution


Given a uniformly charged rod of FINITE length, could we use Gauss' law for electric flux to calculate the field at a point p a distance x away from the rod, so long as the whole rod is enclosed and x lies on the surface area of the enclosing gaussian surface? I tried it with the equation E = λ L/(ε A), but it didn't work. I also found multiple different A's could be used, but none of them gave the right answer. Could someone please explain to me where I'm going wrong with this?
 
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  • #2
Gauss's Law states that
$$\oint\mathbf{E}\cdot d\mathbf{a}=\frac{Q_{enc}}{\epsilon}$$
Normally, there is some kind of symmetry argument which can be made that allows us to know the direction of ##\mathbf{E}##. If the rod was infinitely long, then you could use mirror symmetry and translational symmetry to argue that only the radial component of ##\mathbf{E}## is non-zero at all points. In that case, the dot product ##\mathbf{E}\cdot d\mathbf{a}=E\hat{r}\cdot da\hat{r}=Eda## and we can evaluate the integral. In the case of a finite rod, do these symmetry arguments hold? If they don't then can you evaluate ##\mathbf{E}\cdot d\mathbf{a}##?
 

FAQ: Using Gauss' Law to Calculate electric field near rod.

1. How do you use Gauss' Law to calculate electric field near a rod?

Gauss' Law states that the electric flux through a closed surface is equal to the charge enclosed divided by the permittivity of free space. To use this law to calculate the electric field near a rod, you must first draw a Gaussian surface that encloses the rod. Then, calculate the electric flux through this surface by taking the dot product of the electric field and the surface area vector. Finally, equate this value to the charge enclosed divided by the permittivity of free space and solve for the electric field.

2. What is the significance of choosing a Gaussian surface when using Gauss' Law?

Choosing a Gaussian surface is important because it allows us to simplify the calculation of the electric field. By choosing a surface that is perpendicular to the electric field, the dot product in the calculation of electric flux becomes a simple multiplication. Additionally, by choosing a closed surface, the electric field at all points on the surface will be the same, making the calculation easier.

3. Can Gauss' Law be used for any shape of charge distribution?

Yes, Gauss' Law can be used for any shape of charge distribution as long as the charge is enclosed by the Gaussian surface. However, for more complex shapes, the calculation of the electric field may be more difficult and may require advanced mathematical techniques.

4. How does the electric field near a rod vary with distance?

The electric field near a rod varies inversely with the distance from the rod. This means that as the distance from the rod increases, the electric field decreases. This relationship is represented by the inverse square law, which states that the electric field is proportional to the inverse of the square of the distance.

5. Are there any real-life applications of using Gauss' Law to calculate electric field near a rod?

Yes, there are many real-life applications of using Gauss' Law to calculate electric field near a rod. For example, it can be used to determine the electric field near power lines, which is important for ensuring the safety of individuals living near these power lines. It can also be used in the design of electronic devices, where the electric field near certain components needs to be controlled to prevent damage or malfunction.

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