Using inertia tensor in conservation of angular momentum

In summary, the problem is that the person is not understanding what the different symbols mean in the equation and they are not following the instructions in the solution manual. They are also not getting the right answer to their calculation. They are missing the 'oa' in the cons. of angular momentum equation.
  • #1
Mark24
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Hi all, this is my first post. I'm under the gun at the moment because we were just told yesterday to expect a similar problem to the one below on our final, yet we were not taught how to work such a problem in class. (Our teacher does not write the final hence the discrepancy.)

I have a solution manual I am trying to learn how to do this problem with the help of, but it is not going very well. My book only vaguely touches on the inertia tensor so I'm very confused about what's going on in this problem. I've posted the two pages from the solution manual. I keep trying but I can't seem to duplicate the numbers the solution manual gets.

1)The problem statement, all variables and equations:
Page 1: http://i43.tinypic.com/2j4d761.jpg
Page 2: http://i41.tinypic.com/w1mhg.jpg

2) Attempt at solution
The 'I1' calculation seems to be Izz for a thin plate from the back of my book, where Izz = 1/12*m(a2 + b2). Yet the manual labels that value I1 and seems to use it in place of where Ixx should be in the inertia tensor (Imat.) I don't know if this is an error or not.

And also for Ioa, I'm using the formula Ixx*ux2 + Iyy*uy2 + Izz*uz2 where the u's are the unit vectors for ro/a. Since ux is zero, I should get: Ioa = Iyy*uy2 + Izz*uz2. Again, I'm unsure of which is Iyy and Izz from the solution manual due to the obscure labeling of I1/I2/I3, and I'm unsure of how to identify which is which from the picture. (that's something I never figured out since we are usually given the values)

If anyone can offer some tips or suggestions on this problem, I would be very grateful. After spending about 4 hours staring at it, googling, etc. I'm really at my wits end.
 
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  • #2
Welcome to PF!

Mark24 said:
The 'I1' calculation seems to be Izz for a thin plate from the back of my book, where Izz = 1/12*m(a2 + b2). Yet the manual labels that value I1 and seems to use it in place of where Ixx should be in the inertia tensor (Imat.) I don't know if this is an error or not.

Hi Mark24! Welcome to PF! :smile:

The 1 2 and 3 refer to x y and z, so the I1 is Ixx, which they get by adding Iyy and Izz (the parallel axis theorem).

I don't understand why you're confused … 1,2,3 ~ x,y,z is fairly simple notation :confused:

Anyway, look at the diagram :smile: …​

Izz clearly depends on a, and it's through the c.o.m., so it's small, so it's 1/12

while Iyy clearly depends on b, and it's not through the c.o.m., so it's larger, so it's 1/3 :wink:
 
  • #3
Thanks tiny-tim, how they derived the moments of inertia makes sense now after you explained it. Since the inertias seem to be correct but I'm still getting the wrong answer, I must be messing up the final equation - the one listed in the second picture as:
Imat(0,0,w1)oa = Ioa*w2

For Ioa, I get Ioa = Iyy*uy2 + Izz*uz2 = .192

For Imat, I get a diagonal matrix with values: .4167, .2667, .15. w1 is 2 rad/s.

If I do Imat*(0,0,w1) = Ioa*w2, I get w2 = 1.56 in the z direction and 0 in the y, which is wrong. Any idea what I am missing? The solution has an 'oa' at the end on the left hand side of the equation. oa is the unit vector, so I don't understand why it would be needed in the cons. of angular momentum equation.
 
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  • #4
Hi Mark24! :smile:

(have an omega: ω :wink:)
Mark24 said:
If I do Imat*(0,0,w1) = Ioa*w2, I get w2 = 1.56 in the z direction and 0 in the y, which is wrong. Any idea what I am missing? The solution has an 'oa' at the end on the left hand side of the equation. oa is the unit vector, so I don't understand why it would be needed in the cons. of angular momentum equation.

Imatrix converts the angular velocity vector (0,0,ω1) to the angular momentum vector, Imat*(0,0,ω1).

The external forces are at O and A, so angular momentum is only conserved about the OA axis, so we need the OA-component of the angular momentum vector:

Imat*(0,0,ω1) "dot" oa :wink:
 

FAQ: Using inertia tensor in conservation of angular momentum

What is the inertia tensor?

The inertia tensor is a mathematical representation of an object's mass distribution and rotational inertia. It is a 3x3 matrix that describes how an object's mass is distributed around its axis of rotation.

How is the inertia tensor used in conservation of angular momentum?

The inertia tensor is used in the conservation of angular momentum to calculate the angular momentum of a rotating object. It is used in the equation L = Iω, where L is the angular momentum, I is the inertia tensor, and ω is the angular velocity.

What is the significance of the inertia tensor in physics?

The inertia tensor is significant in physics as it allows us to understand and predict the rotational motion of objects. It is also used in various applications such as spacecraft navigation, aerospace engineering, and robotics.

How is the inertia tensor calculated?

The inertia tensor is calculated by integrating the mass of an object over its volume using the formula I = ∫r²dm, where r is the distance from the object's axis of rotation and dm is the infinitesimal mass element.

Can the inertia tensor change for a rotating object?

Yes, the inertia tensor can change for a rotating object if its mass distribution changes. For example, if an object extends or contracts along its axis of rotation, its inertia tensor will also change.

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