Using Momentum Principle to Find Ratio of Speeds?

In summary, the article discusses how to apply the momentum principle to determine the ratio of speeds in various physical systems. It explains the foundational concepts of momentum, including conservation laws, and illustrates how these principles can be used to relate the speeds of different objects before and after collisions or interactions. The article provides examples and mathematical formulations to demonstrate the practical application of the momentum principle in solving problems related to speed ratios.
  • #1
Spooky123
3
0
Homework Statement
Two different experiments are performed. In the first experiment, a constant force is applied to a hydrogen ion. In the second experiment, the same constant applied force is applied to an ion that has a mass 12 times the mass of hydrogen. In each experiment, the ion is at rest at location A. Note that this force is much larger than any possible gravitational force on the ions, so you can neglect gravity.
Relevant Equations
Derive an expression for the final y-velocity of an ion as a function of its mass, the time interval At, and the force on the ion F.

Pf = Pi + FnetT
Vavg = v1 + v2 / 2
Vavg = r/t
Given that the ions are initially at rest my initial velocity is 0. Therefore my Vavg is equal to vf/2
Using the formula Vavg = Change in positon/time, I can solve vf to be equal to 2r/t.

Using the momentum principle, I get an equation of 2r/t = FnetT/12m -> Given that the mass of the ion is 12x Hydrogen.

However, when I solve for FnetT/12m divided by FnetT/m I get a ration of 1/12. Which is incorrect...

This question should only use the momentum principle and velocity equations without having to involve acceleration.
 
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  • #2
Spooky123 said:
Homework Statement: Two different experiments are performed. In the first experiment, a constant force is applied to a hydrogen ion. In the second experiment, the same constant applied force is applied to an ion that has a mass 12 times the mass of hydrogen. In each experiment, the ion is at rest at location A. Note that this force is much larger than any possible gravitational force on the ions, so you can neglect gravity.
Relevant Equations: Derive an expression for the final y-velocity of an ion as a function of its mass, the time interval At, and the force on the ion F.

Pf = Pi + FnetT
Vavg = v1 + v2 / 2
Vavg = r/t

Given that the ions are initially at rest my initial velocity is 0. Therefore my Vavg is equal to vf/2
Using the formula Vavg = Change in positon/time, I can solve vf to be equal to 2r/t.

Using the momentum principle, I get an equation of 2r/t = FnetT/12m -> Given that the mass of the ion is 12x Hydrogen.

However, when I solve for FnetT/12m divided by FnetT/m I get a ration of 1/12. Which is incorrect...

This question should only use the momentum principle and velocity equations without having to involve acceleration.
If you are acting on both ions for the same amount of time, then
##v = v_0 + aT##

Assuming that ##v_0 = 0## m/s for both, then
##v = aT##.

Now, ##F = ma##, so
##v = \dfrac{FT}{m}##

So, for Hydrogen:
##v = \dfrac{FT}{m}##

Let's call the other ion carbon. So for carbon:
##V = \dfrac{FT}{12m}##

The ratio of these will be

##\dfrac{V}{v} = \dfrac{1}{12}##

as you said above.

-Dan
 
  • #3
Spooky123 said:
Pf = Pi + FnetT
This question should only use the momentum principle and velocity equations without having to involve acceleration.
You have all the ingredients above to do what you are asked. Remember that pi = 0. You don't need any velocity or acceleration equations.
 
  • #4
The correct answer for this question is 0.2889. I guess it might be an error.
 
  • #5
Spooky123 said:
The correct answer for this question is 0.2889. I guess it might be an error.
How can the correct answer be a number (with no units) when the task is to "Derive an expression for the final y-velocity of an ion as a function of its mass, the time interval At, and the force on the ion F"?
 
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FAQ: Using Momentum Principle to Find Ratio of Speeds?

What is the Momentum Principle?

The Momentum Principle, also known as the principle of conservation of momentum, states that the total momentum of a closed system remains constant if no external forces act on it. It is mathematically expressed as the change in momentum being equal to the net external force acting on the system multiplied by the time interval over which the force acts.

How is the Momentum Principle used to find the ratio of speeds?

To find the ratio of speeds using the Momentum Principle, you first identify the initial and final momenta of the objects involved. By applying the conservation of momentum (initial momentum equals final momentum), you can set up equations to solve for the final speeds of the objects. The ratio of these speeds can then be determined by dividing one speed by the other.

What are the key steps in applying the Momentum Principle to a collision problem?

The key steps are: (1) Identify the system and ensure no external forces are acting on it, (2) Calculate the total initial momentum of the system, (3) Calculate the total final momentum of the system, (4) Set the total initial momentum equal to the total final momentum, and (5) Solve for the unknown speeds and determine their ratio.

Can the Momentum Principle be applied to both elastic and inelastic collisions?

Yes, the Momentum Principle can be applied to both elastic and inelastic collisions. In elastic collisions, both momentum and kinetic energy are conserved. In inelastic collisions, only momentum is conserved, while kinetic energy is not necessarily conserved. The principle helps in determining the final velocities in both types of collisions.

What role does mass play in finding the ratio of speeds using the Momentum Principle?

Mass plays a crucial role because momentum is the product of mass and velocity. When using the Momentum Principle, the masses of the objects involved directly affect the calculations of their momenta. The ratio of speeds is influenced by the masses, as the final velocities are derived from the relationship between mass and momentum conservation.

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