- #1
Telemachus
- 835
- 30
Homework Statement
Hi there. I'm having some trouble with this exercise, which says: Use the Newton's method for determining the zeros of f(x) to 5 decimal places for [tex]f(x)=x^5+x-1[/tex].
So [tex]f'(x)=5x^4+1[/tex]
I thought of iterating till I get [tex]x_n-x_{n+1}<0.000001[/tex]. The thing is that I get to a point where the calculus become too difficult because of the numbers dimensions.
I've started with x=1
[tex]x_1=1\Rightarrow{x_2=1-\displaystyle\frac{1}{6}}=\displaystyle\frac{5}6{}[/tex]
[tex]x_3=\displaystyle\frac{5}{6}-\displaystyle\frac{1829}{11526}=\displaystyle\frac{1296}{1921}[/tex]
From here it becomes to difficult to continue.
[tex]f(x_3)=\displaystyle\frac{1296^5}{1921^5}+\displaystyle\frac{1296}{1921}-1[/tex]
[tex]f'(x_3)=5\displaystyle\frac{1296^4}{1921^4}[/tex]
And I still too far from the five decimal places that it asks me for.
I have this formula too, which I don't know how to use
It says:
Being [tex]f:[a,b]\longrightarrow{\mathbb{R}}[/tex] a function two times derivable on the compact interval [a,b] such that 1º) f(a) and f(b) have different sign; 2º) exists [tex]k_1<0[/tex] such that [tex]|f'(x)|\geq{k_1}[/tex] for all [tex]x\in{I}[/tex]; and 3º) exists [tex]k_2\in{\mathbb{R}}[/tex] such that [tex]|f''(x)|\leq{k_2}[/tex] for all [tex]x\in{I}[/tex]. Then it verifies:
1.º In ]a,b[ there is only one root r of the equation f(x)=0
2.º If r is enclosed on an interval [tex] [r-\delta,r+\delta]\subset{[a,b]}[/tex] with [tex]\delta<2(k_1/k_2)[/tex] and if we take [tex]x_1[/tex] on the interval, the succession [tex]x_n[/tex] defined by recurrence by
[tex]x_{n+1}=x_n-\displaystyle\frac{f(x_n)}{f'(x_n)}, (n\in{\mathbb{N}})[/tex] (Newton iteration)
converges to the root r, and it verifies
[tex]|x_{n+1}-r|<\displaystyle\frac{k_2}{2k_1}|x_n-r|^2[/tex] y [tex]|x_{n+1}-r|<\displaystyle\frac{2k_1}{k_2}(\delta/\displaystyle\frac{2k_1}{k_2})^{2n}[/tex]Can I use this last to know how many iterations I'll have to use to get the error that it asks me for?
Bye there, and thanks.