Using Taylor Formula to Find Series of f(x)=e^{2x}

In summary, the Taylor Formula is a mathematical tool used to approximate a function using a polynomial. It is derived from the Taylor Series, an infinite sum of terms that approximates a function at a specific point. To find the series of a function using the Taylor Formula, a point is chosen and the derivatives of the function at that point are used to create the coefficients of the polynomial. This allows for easier calculations and a better understanding of the function's behavior. While the Taylor Formula can be used for any differentiable function, the accuracy of the approximation depends on the smoothness of the function and the chosen point.
  • #1
dejet
6
0

Homework Statement


using the Taylor Formula, find the series for the function f(x)=e^{2x}

Homework Equations


[tex]\sum \frac{f^{n}(a)}{n!} (x-a)^{n}[/tex]

any help as to where i start would be great. new to series...
 
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  • #2
dejet said:

Homework Statement


using the Taylor Formula, find the series for the function f(x)=e^{2x}

Homework Equations


[tex]\sum \frac{f^{n}(a)}{n!} (x-a)^{n}[/tex]

any help as to where i start would be great. new to series...
You missed out one important section:
Homework Help Template said:

The Attempt at a Solution

Even if you are new to series, you must have some idea of how to start.
 
  • #3
e^2x= 1+2x+ [tex]\frac{2x^{2}}{2!} +\frac{2x^{3}}{3!} +\frac{2x^{4}}{4!}+...[/tex]

there is more to it i think.
 
  • #4
dejet said:
e^2x= 1+2x+ [tex]\frac{2x^{2}}{2!} +\frac{2x^{3}}{3!} +\frac{2x^{4}}{4!}+...[/tex]

there is more to it i think.
No, that isn't correct. The question states that you must use Taylor's formula, have you tried using it?
 
  • #5
dejet said:
e^2x= 1+2x+ [tex]\frac{2x^{2}}{2!} +\frac{2x^{3}}{3!} +\frac{2x^{4}}{4!}+...[/tex]

there is more to it i think.

e^x = 1 + x + x^2/2!+ x^3/3! + ...

You substituted 2x for x

so .. x^2 should be (2x)^2 not 2x^2
 
  • #6
rootX said:
e^x = 1 + x + x^2/2!+ x^3/3! + ...

You substituted 2x for x

so .. x^2 should be (2x)^2 not 2x^2
To the OP: Although, substituting 2x for x in the Taylor series for ex as rootX has done is a totally valid (and preferable) method, the question specifically states that Taylor's Formula should be used. Try using it.
 
  • #7
so is this right?

2^(n-1) f(x)=1+2x+4x^2/2!+8x^3/3!+...+2^(n-1)/(n!)...
 
  • #8
dejet said:
so is this right?

2^(n-1) f(x)=1+2x+4x^2/2!+8x^3/3!+...+2^(n-1)/(n!)...

no!

Steps:
1. Find f' , f'', f''', ... for f(x) = e^(2x)
2. plug values in your taylor formula

No straight jumping to the answer.
 

FAQ: Using Taylor Formula to Find Series of f(x)=e^{2x}

What is the Taylor Formula used for?

The Taylor Formula is a mathematical tool used to approximate a function using a polynomial. It helps to find a series of terms that can closely represent the original function.

How is the Taylor Formula derived?

The Taylor Formula is derived from the Taylor Series, which is an infinite sum of terms that approximates a function at a specific point. The formula is a finite version of the series, making it easier to use for calculations.

How is the Taylor Formula used to find the series of a function?

To find the series of a function using the Taylor Formula, we need to first choose a point around which we want to approximate the function. Then, we calculate the derivatives of the function at that point. These derivatives are used to create the coefficients of the polynomial, which is the series of the function.

What is the significance of using the Taylor Formula to find a series?

The Taylor Formula allows us to approximate a function with a polynomial, which is often easier to work with in calculations. It also helps us to better understand the behavior of a function around a specific point and can be used to make predictions about the function's values at other points.

Can the Taylor Formula be used for any type of function?

Yes, the Taylor Formula can be used for any differentiable function. However, the accuracy of the approximation depends on the smoothness of the function and the chosen point around which the series is calculated. Functions with high derivatives at the chosen point will have a more accurate series.

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