- #1
evinda
Gold Member
MHB
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Hello! (Wave)
I want to show the embedding $W^{1,p}(0,1) \subset C^0 [0,1]$.
So we pick a $u \in W^{1,p}(0,1)$ and want to show that $u \in C^0 [0,1]$.
Let $x_n \to x$. We want to show that $u(x_n) \to u(x)$.
Since $u \in W^{1,p}(0,1)$ we have that $u \in L_p$ and $u' \in L_p$.
And you told me to use the fact that $u(x+h)-u(x)=\int_{x}^{x+h} u'(t) dt$.
We know that a function $f$ is continuous in $x_0$ if $\forall \epsilon>0 \exists \delta>0$ such that $\forall y \in [x,x+h]$ with $|y-x_0|< \delta$ it holds that $|f(y)-f(x_0)|< \epsilon$.
Can we use this definition for $f=u, x_0=x, y=x+h$ ?
I want to show the embedding $W^{1,p}(0,1) \subset C^0 [0,1]$.
So we pick a $u \in W^{1,p}(0,1)$ and want to show that $u \in C^0 [0,1]$.
Let $x_n \to x$. We want to show that $u(x_n) \to u(x)$.
Since $u \in W^{1,p}(0,1)$ we have that $u \in L_p$ and $u' \in L_p$.
And you told me to use the fact that $u(x+h)-u(x)=\int_{x}^{x+h} u'(t) dt$.
We know that a function $f$ is continuous in $x_0$ if $\forall \epsilon>0 \exists \delta>0$ such that $\forall y \in [x,x+h]$ with $|y-x_0|< \delta$ it holds that $|f(y)-f(x_0)|< \epsilon$.
Can we use this definition for $f=u, x_0=x, y=x+h$ ?